Tìm X
X x 6 = 30
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\(\Rightarrow-3x=\dfrac{6}{7}-\dfrac{30}{21}\\ \Rightarrow-3x=\dfrac{18}{21}-\dfrac{30}{21}\\\Rightarrow-3x=\dfrac{-12}{21}\\ \Rightarrow x=\dfrac{-12}{21}:3\\ \Rightarrow x=\dfrac{-12}{63}=\dfrac{-4}{21} \)
đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
0,75 x X + 0,75 x X + X = 30
X x ( 0,75 + 0,75 + 1 ) = 30
X x 2,5 = 30
X = 30 : 2,5
X = 12
75%xX+3/4xX+X=30
<=>3/4xX+3/4xX+X=30
<=>10/4xX=30
<=>10xX=120
<=>X=120/10=12
Vậy X=12
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\cdot\frac{5}{2}=30\)
\(x=30\cdot\frac{2}{5}\)
\(x=12\)
a)\(\Leftrightarrow\)\(x(27+30+43)=210500\)
\(\Leftrightarrow\)\(100x=210500\)
\(\Leftrightarrow\)\(x=2105\)
b)\(\Leftrightarrow\)\(x(128-12-16)=5208000\)
\(\Leftrightarrow\)\(100x=5208000\)
\(\Leftrightarrow\)\(x=52080\)
\(x\times27+x\times30+x\times43=210500\)
\(\Leftrightarrow x\times\left(27+30+43\right)=210500\)
\(\Leftrightarrow x\times100=210500\)
\(\Leftrightarrow x=2105\)
x+ \(\dfrac{30}{100}\)x=-1,3
x(1+\(\dfrac{30}{100}\))= -1,3
x. 1,3= -1,3
x = -1
ĐKXĐ: \(x\ge-1\)
\(\Leftrightarrow6-\sqrt{x+1}-x-1=0\\ \Leftrightarrow5-x=\sqrt{x+1}\\ \Leftrightarrow25-10x+x^2=x+1\left(x\le5\right)\\ \Leftrightarrow x^2-11x+24=0\\ \Leftrightarrow\left(x^2-3x\right)-\left(8x-24\right)=0\\ \Leftrightarrow x\left(x-3\right)-8\left(x-3\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x-8\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=3\left(tm\right)\\x=8\left(ktm\right)\end{matrix}\right.\)
Vậy \(x=3\)
X x 6 = 30
X = 30 : 6
X = 6