BC 42,24,60
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a)`BC (24;20;30); 4=23.3; 20=22.5; 30=2.3.5; ` suy ra `BCNN(24;20;30)=23.3.5=120 suy ra `BC(24;20;30)=`B(120)=\(\left\{0;120;240;360;....\right\}\) b)BC(2;3;7;5); ` 2=2; 3=3; 7=7; 5=5; ` suy ra` `BCNN(2;3;5;7)=2.3.5.7=210 suy ra `BC`(2;3;5;7)=B(210)=\(\left\{0;210;420;630;...\right\}\)
c)BC(34;45;54); 34=2.17; 45=32.5; 54=2.33; suy raBCNN(34;45;54)=2.33.5.17=4590 suy ra BC(34;45;54)=B(4590)=\(\left\{0;4590;9180;13770;...\right\}\)
a) BC (5;3) = {0;15;30;45;...}.
b) BC( 4;20) = {0 ; 20; 40;…}
c) BC (24; 16) = (0;48;96;144...)
d) BC (8; 12; 24) = (0; 24; 48; ...}.
a: \(84=2^2\cdot3\cdot7;108=3^3\cdot2^2\)
=>\(BCNN\left(84;108\right)=2^2\cdot3^3\cdot7=756\)
=>\(BC\left(84;108\right)=\left\{756;1512;2268;...\right\}\)
b: \(98=2\cdot7^2;72=2^3\cdot3^2;42=2\cdot3\cdot7\)
=>\(BCNN\left(98;72;42\right)=2^3\cdot7^2\cdot3^2=3528\)
=>\(BC\left(98;72;42\right)=\left\{3528;7056;...\right\}\)
c: \(68=2^2\cdot17;208=2^4\cdot13;100=2^2\cdot5^2\)
=>\(BCNN\left(68;208;100\right)=2^4\cdot13\cdot5^2\cdot17=88400\)
=>\(BC\left(68;208;100\right)=\left\{88400;176800;...\right\}\)
a: Xét ΔABC có:
AB+AC>BC(BĐT tam giác)
b: Xét ΔABC có AB+AC>BC(BĐT tam giác)
d: (AB+AC)^2=AB^2+AC^2+2*AB*AC
=BC^2+2*AH*BC<BC^2+2*AH*BC+AH^2=(BC+AH)^2
=>AB+AC<AH+BC
TL:
BCNN 42,24,60=840
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