Tính
a) 28 + (– 7)
b) (– 36) + 60
c) 60 + (– 180)
d) (– 39) + 35
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a) 28 = 2 2 . 7 ; 70 = 2.5.7 .Vậy ƯCLN(28,70) = 2.7 = 14
b) ƯCLN(36, 60,72) =12
c) ƯCLN(60,180) = 60
d) ƯCLN(28, 39, 35) = 1
a) \(\dfrac{3}{10}\)
b) \(\dfrac{9}{28}\)
c) \(\dfrac{88}{195}\)
a) 40=23.5
60=22.3.5; ƯCLN(40,60)=22.5=20
b)36=22.32
60=22.3.5; ƯCLN(36,60)=22.3=12
c)13=13
20=22.5; ƯCLN(13,20)=1
d)28=22.7
39=3.13
35=5.7; ƯCLN(28,39,35)=1
a) 40=23.5
60=22.3.5; ƯCLN(40,60)=22.5=20
b)36=22.32
60=22.3.5; ƯCLN(36,60)=22.3=12
c)13=13
20=22.5; ƯCLN(13,20)=1
d)28=22.7
a, Ta có: \(40=2^3.5\\ 60=2^2.3.5\\ =>ƯCLN\left(40;60\right)=2^2.5=20\)
b, \(36=2^2.3^2\\ 60=2^2.3.5\\ 72=2^3.3^2\\ =>ƯCLN\left(36;60;72\right)=2^2.3=12\)
c, \(13=13.1\\ 20=2^2.5\\ =>ƯCLN\left(13;20\right)=1\)
d, \(28=2^2.7\\ 39=39.1\\ 35=7.5\\ =>ƯCLN\left(28;39;35\right)=1\)
a) UCLN(40, 60)
Ta có: 40 = 23.5
60 = 22.3.5
UCLN(40, 60) = 22.5 = 20
b) UCLN(13, 20)
Ta có: 13 = 13
20 = 22.5
UCLN(13, 20) = 1
c) UCLN(36, 60, 72)
Ta có: 36 = 22.32
60 = 22.3.5
72 = 23.32
UCLN(36, 60, 70) = 22.3 = 12
d) UCLN(28, 39, 35)
Ta có: 28 = 22.7
39 = 39
35 = 5.7
UCLN(28, 39, 35) = 1
a) ƯCLN(40; 60)=20
b) ƯCLN(36; 60; 72)=12
c) ƯCLN(13;20)=1
d) ƯCLN(28; 39; 35;)=1
Bài 1:
a: =25+75=100
b: =60-17-43+12=12
c: =-2-18=-20
d: =-3+36-17=36-20=16
Bài 2:
a: =-102
b: =-1000
c: =12x15=180
d: =21x(-10)=-210
Bài làm :
\(a,35.34+35.38+65.75+65.45\)
\(=35.\left(34+38\right)+65.\left(74+45\right)\)
\(=35.72+65.120\)
\(=2520+780\)
\(=10320\)
\(b,39.8+60.2+21.8\)
\(=\left(39+21\right).8+60.2\)
\(=60.8+60.2\)
\(=60.\left(8+2\right)\)
\(=60.10=600\)
\(c,36.28+36.82+64.69+64.4\)
\(=36.\left(28+82\right)+64.\left(69+4\right)\)
\(=36.110+64.73\)
\(=3960+4672\)
\(=8632\)
\(d,123.1001\)
\(=123123\)
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