2x + 15=142:2
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Tập xác định D = R.
Giải từng bất phương trình:
Vậy tập nghiệm của hệ bất phương trình là
\(5-\dfrac{2}{3}-\dfrac{14}{15}+\dfrac{1}{35}-\dfrac{62}{63}-\dfrac{98}{99}-\dfrac{142}{143}\)
\(=5-\left(1-\dfrac{1}{3}\right)-\left(1-\dfrac{1}{15}\right)+\dfrac{1}{35}-\left(1-\dfrac{1}{63}\right)-\left(1-\dfrac{1}{99}\right)-\left(1-\dfrac{1}{143}\right)\)
\(=5-1+\dfrac{1}{1\cdot3}-1+\dfrac{1}{3\cdot5}+\dfrac{1}{5\cdot7}-1+\dfrac{1}{7\cdot9}-1+\dfrac{1}{9\cdot11}-1+\dfrac{1}{11\cdot13}\)
\(=1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+...+\dfrac{1}{11}-\dfrac{1}{13}\)
\(=1-\dfrac{1}{13}=\dfrac{12}{13}\)
a) \(x+5=20-\left(12-7\right)\)
\(\Rightarrow x+5=20-5\)
\(\Rightarrow x+5=15\)
\(\Rightarrow x=15-5\)
\(\Rightarrow x=10\)
b) \(15-\left(3+2x\right)=2^2\)
\(\Rightarrow3+2x=15-4\)
\(\Rightarrow3+2x=11\)
\(\Rightarrow2x=11-3\)
\(\Rightarrow2x=8\)
\(\Rightarrow x=\dfrac{8}{2}\)
\(\Rightarrow x=4\)
c) \(-11-\left(19-x\right)=50\)
\(\Rightarrow19-x=-11-50\)
\(\Rightarrow19-x=-61\)
\(\Rightarrow x=61+19\)
\(\Rightarrow x=80\)
d) \(159-\left(25-x\right)=43\)
\(\Rightarrow25-x=159-43\)
\(\Rightarrow25-x=116\)
\(\Rightarrow x=25-116\)
\(\Rightarrow x=-91\)
e) \(\left(79-x\right)-43=-\left(17-52\right)\)
\(\Rightarrow\left(79-x\right)-43=52-17\)
\(\Rightarrow79-x-43=35\)
\(\Rightarrow36-x=35\)
\(\Rightarrow x=1\)
f) \(\left(7+x\right)-\left(21-13\right)=32\)
\(\Rightarrow7+x-8=32\)
\(\Rightarrow x-1=32\)
\(\Rightarrow x=32+1\)
\(\Rightarrow x=33\)
g) \(-x+20=-15+8+13\)
\(\Rightarrow-x+20=6\)
\(\Rightarrow x=20-6\)
\(\Rightarrow x=14\)
h) \(-\left(-x+13-142\right)+18=55\)
\(\Rightarrow x-13+142+18=55\)
\(\Rightarrow x+147=55\)
\(\Rightarrow x=55-147\)
\(\Rightarrow x=-92\)
\(3.\left[\left(2x-1\right)^2-4\right]-14^2=7^2.5^3:175\)
\(=>3.\left[\left(2x-1\right)^2-4\right]-14^2=35\)
\(=>3.\left[\left(2x-1\right)^2-4\right]=35+14^2=35+196\)
\(=>3.\left[\left(2x-1\right)^2-4\right]=231\)
\(=>\left(2x-1\right)^2-4=231:3\)
\(=>\left(2x-1\right)^2-4=77\)
\(=>\left(2x-1\right)^2=77+4\)
\(=>\left(2x-1\right)^2=81=9^2\)
\(\Rightarrow2x-1=9\)
\(=>2x=9+1\)
\(=>2x=10\)
\(=>x=10:2\)
\(=>x=5\)
Vậy:...
# Wendy Dang
3.[(2x + 1)² - 4] - 14² = 7².5³:175
3.[(2x - 1)² - 4] - 196 = 49.125:175
3.[(2x - 1)² - 4] - 196 = 35
3.[(2x - 1)² - 4] = 35 + 196
3.[(2x - 1)² - 4] = 231
(2x - 1)² - 4 = 231 : 3
(2x - 1)² - 4 = 77
(2x - 1)² = 77 + 4
(2x - 1)² = 81
2x - 1 = 9 hoặc 2x - 1 = -9
*) 2x - 1 = 9
2x = 9 + 1
2x = 10
x = 10 : 2
x = 5 (nhận)
*) 2x - 1 = -9
2x = -9 + 1
2x = -8
x = -8 : 2
x = -4 (loại)
Vậy x = 5
Sửa đề: \(98+99+\dfrac{142}{144}\) \(\rightarrow\dfrac{98}{99}+\dfrac{143}{144}\)
Giải:
\(A=\dfrac{2}{3}+\dfrac{14}{15}+\dfrac{34}{35}+\dfrac{62}{63}+\dfrac{98}{99}+\dfrac{143}{144}+\dfrac{194}{195}\)
\(A=\left(1-\dfrac{1}{3}\right)+\left(1-\dfrac{1}{15}\right)+\left(1-\dfrac{1}{35}\right)+...+\left(1-\dfrac{1}{195}\right)\)
\(A=7-\left(\dfrac{1}{3}+\dfrac{1}{15}+\dfrac{1}{35}+...+\dfrac{1}{195}\right)\)
\(A=7-\left(\dfrac{1}{1.3}+\dfrac{1}{3.5}+\dfrac{1}{5.7}+...+\dfrac{1}{13.15}\right)\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{2}{1.3}+\dfrac{2}{3.5}+\dfrac{2}{5.7}+...+\dfrac{2}{13.15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{13}-\dfrac{1}{15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\left(\dfrac{1}{1}-\dfrac{1}{15}\right)\right]\)
\(A=7-\left[\dfrac{1}{2}.\dfrac{14}{15}\right]\)
\(A=7-\dfrac{7}{15}\)
\(A=\dfrac{98}{15}\)
Chúc bạn học tốt!
a ) x = 43 30 x = − 43 30 ; b ) x = 3 2 x = 7 6 . c ) x = 13 6 x = 1 2
d ) x = − 94 45 x = 164 45 ; e ) x = 7 8 x = − 3 8 . f ) x = 7 8 x = − 3 8