Tinh hop ly:\(\left(999^2+888^2+777^2\right)\times\left(100000000-2^8\times5^6\right)\)
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(1-1/3)x(1-1/5)x(1-1/7)x(1-1/9)x(1-1/2)x(1-1/4)x(1-1/6)x(1-1/8)x(1-1/10)
=2/3x4/5x6/7x8/9x1/2x3/4x5/6x7/8x9/10
=2x4x6x8x1x3x5x7x9 /3x5x7x9x2x4x6x8x10
=1/10
c
\(=160:\left\{17+\left[9\cdot5-\left(14+2^3\right)\right]\right\}\)
\(=160:\left\{17+\left[45-\left(14+8\right)\right]\right\}\)
\(=160:\left\{17+\left[45-22\right]\right\}\)
\(=160:\left(17+23\right)\)
\(=160:40\)
\(=4\)
d
\(=798+100:\left[16-2\cdot\left(25-22\right)\right]\)
\(=798+100:\left(16-2\cdot3\right)\)
\(=798+100:\left(16-6\right)\)
\(=798+100:10\)
\(=798+10\)
\(=808\)
a: TH1: x<2
Pt sẽ là 5-x+2-x=5x
=>5x=-2x+7
=>x=1(nhận)
TH2: 2<=x<5
Pt sẽ là 5x=x-2+5-x=3
=>x=3/5(loại)
TH3: x>=5
Pt sẽ là 5x=x-5+x-2=2x-7
=>3x=-7
=>x=-7/3(loại)
b: \(A=\dfrac{2^6\cdot5^2+2^{11}\cdot5^9}{2^{16}\cdot5^7+2^{16}\cdot5^8}\)
\(=\dfrac{2^6\cdot5^2\left(1+2^5\cdot5^7\right)}{2^{16}\cdot5^7\left(1+5\right)}=\dfrac{1+2^5\cdot5^7}{2^{10}\cdot5^5\cdot6}\)
\(A=\frac{1}{2}\left(1+\frac{1}{1\cdot3}\right)\left(1+\frac{1}{2\cdot4}\right)...\left(1+\frac{1}{2015\cdot2017}\right)\)\(A=\frac{1}{2}\left(\frac{1\cdot3+1}{1\cdot3}\right)\left(\frac{2\cdot4+1}{2\cdot4}\right)...\left(\frac{2015\cdot2017+1}{2015\cdot2017}\right)\)
\(A=\frac{1^2}{2}\cdot\frac{2^2}{1\cdot3}\cdot\frac{3^2}{2\cdot4}\cdot\cdot\cdot\frac{2016^2}{2015\cdot2017}\)
\(A=\frac{1^2\cdot2^2\cdot3^2\cdot\cdot\cdot2016^2}{2\cdot1\cdot3\cdot2\cdot4\cdot\cdot\cdot2015\cdot2017}\)
\(A=\frac{2016}{2017}\)
\(\frac{\left(2^3\cdot5\cdot7\right)\cdot\left(5^2\cdot7^3\right)}{\left(2\cdot5\cdot7\right)^2}\)
\(=\frac{2^3\cdot5^3\cdot7^4}{2^2\cdot5^2\cdot7^2}\)
\(=2\cdot5\cdot7^2\)
\(=10\cdot49=490\)
\(\frac{\left(2^3.5.7\right).\left(5^2.7^3\right)}{\left(2.5.7\right)^2}\)
\(=\frac{2^3.5^3.7^4}{2^2.5^2.7^2}\)
\(=2.5.7^2\)
\(=\left(2.5\right).7^2\)
\(=10.49\)
\(=490\)
thấy hay thì tick nhé mọi người
tích đi sau lamg cho dễ mà
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