a) 27 3 x 5 48
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a. \(x:3+27=48.2\)
\(\Leftrightarrow x:3+27=96\)
\(\Leftrightarrow x:3=96-27\)
\(\Leftrightarrow x:3=69\)
\(\Leftrightarrow x=69.3\)
\(\Leftrightarrow x=207\)
a) x : 3 + 27 = 48 x 2
x : 3 + 27 = 96
x : 3 = 96 - 27
x : 3 = 69
x = 69 x 3
x = 207
b)X x 5 : 7 = 123 -118
X x 5 : 7 = 5
X x 5 = 5 x 7
X x 5 = 35
x = 35 : 5
x = 7
bài 1:
\(a,21^{15}=3^{15}\times7^{15}\)
\(27^5\times49^8=3^{15}\times7^{16}\)
Vậy: \(21^{15}< 27^5\times49^8\)
\(b,27^5=3^{15}\)
\(243^3=3^{15}\)
Vậy: \(27^5=243^3\)
Bài 2:
\(10^x+48=48^y\)
=100..0+48=\(48^y\)
=100...048=\(48^y\)
còn các bước tiếp mik chưa nghĩ ra cậu suy nghĩ thêm nhé
Lời giải:
a. $=(327-27)+(216-16)+600=300+200+600=1100$
b. $=16\times 48+16\times 24+16\times 28$
$=16\times (48+24+28)=16\times 100=1600$
6, \(x=\dfrac{9}{2}+\dfrac{1}{2}=\dfrac{10}{2}=5\)
7, \(x=-\dfrac{3}{4}-\dfrac{5}{4}=-\dfrac{8}{4}=-2\)
8, \(x=\dfrac{5}{7}-\dfrac{2}{7}=\dfrac{3}{7}\)
9, \(x=\dfrac{1}{3}+\dfrac{4}{3}=\dfrac{5}{3}\)
10, \(x=-\dfrac{7}{2}-\dfrac{5}{2}=-\dfrac{12}{2}=-6\)
\(6,x-\dfrac{1}{2}=\dfrac{9}{2}\Leftrightarrow x=5\)
\(7,x+\dfrac{5}{4}=\dfrac{-3}{4}\Leftrightarrow x=-2\)
\(8,x+\dfrac{2}{7}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{3}{7}\)
\(9,x-\dfrac{4}{3}=\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{3}\)
\(10,x+\dfrac{5}{2}=\dfrac{-7}{2}\Leftrightarrow x=-6\)
a: \(=3\sqrt{5}+2\sqrt{5}-2\sqrt{5}=3\sqrt{5}\)
b: \(=2\sqrt{2}+2\sqrt{2}+5\sqrt{2}=9\sqrt{2}\)
c: \(=4\sqrt{3}+3\sqrt{3}-3\sqrt{5}+2\sqrt{5}=7\sqrt{3}-\sqrt{5}\)
d: \(=5\sqrt{3}+4\sqrt{3}-10\sqrt{3}=-\sqrt{3}\)
e: \(=\left(\sqrt{7}-2\sqrt{3}\right)\cdot\sqrt{7}+2\sqrt{21}\)
=7-2*căn 21+2*căn 21
=7
f: \(=\left(2\sqrt{11}-3\sqrt{2}\right)\cdot\sqrt{11}+3\sqrt{22}\)
=22-3*căn 22+3*căn 22
=22
a) \(3\sqrt{5}+\sqrt{20}-2\sqrt{5}\)
\(=3\sqrt{5}+2\sqrt{5}-2\sqrt{5}\)
\(=3\sqrt{5}\)
b) \(2\sqrt{2}+\sqrt{8}+\sqrt{50}\)
\(=2\sqrt{2}+2\sqrt{2}+5\sqrt{2}\)
\(=9\sqrt{5}\)
c) \(4\sqrt{3}+\sqrt{27}-\sqrt{45}+2\sqrt{5}\)
\(=4\sqrt{3}+3\sqrt{3}-3\sqrt{5}+2\sqrt{5}\)
\(=7\sqrt{3}-\sqrt{5}\)
d) \(\sqrt{75}+\sqrt{48}-\sqrt{300}\)
\(=5\sqrt{3}+4\sqrt{3}-10\sqrt{3}\)
\(=-\sqrt{3}\)
e) \(\left(\sqrt{28}-\sqrt{12}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
\(=\left(2\sqrt{7}-2\sqrt{3}-\sqrt{7}\right)\sqrt{7}+2\sqrt{21}\)
\(=\left(\sqrt{7}-2\sqrt{3}\right)\sqrt{7}+2\sqrt{21}\)
\(=7-2\sqrt{21}+2\sqrt{21}\)
\(=7\)
f) \(\left(\sqrt{99}-\sqrt{18}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
\(=\left(3\sqrt{11}-3\sqrt{2}-\sqrt{11}\right)\sqrt{11}+3\sqrt{22}\)
\(=\left(2\sqrt{11}-3\sqrt{2}\right)\sqrt{11}+3\sqrt{22}\)
\(=22-3\sqrt{22}+3\sqrt{22}\)
\(=22\)
g) \(3\sqrt{45}-5\sqrt{125x}+7\sqrt{20x}+28\)
\(=9\sqrt{5}-25\sqrt{5x}+14\sqrt{5x}+28\)
\(=9\sqrt{5}-11\sqrt{5x}+28\)
a: \(=3\sqrt{3}-2\sqrt{3}+4\sqrt{3}-5\sqrt{3}=2\sqrt{3}\)
a) \(\text{48+(3x-18)=17}\)
\(3x-18=27-48\)
\(3x-18=-24\)
\(3x=\left(-24\right)+18\)
\(3x=-6\)
\(x=\left(-6\right):3\)
\(x=-3\)
3x-18=27-48 3x-18=-21 3x=21+18 3x=39 => x=13 . Ý b đề bài k rõ ràng
1000 - 47 . 72 - 47 .28
= 47 . ( 1000 - 72 -28 )
= 47 .0
=0
3457 - 27 . 48 - 48 .73 + 6543
=3457 - 48 . (27 + 73 ) + 6543
= 3457 - 4800 + 6543
= 5200