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\(\frac{x^2}{x^2-4x}\)+\(\frac{6}{6-3x}\)+\(\frac{1}{x+2}\)
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14 tháng 4 2019
\(=\frac{\left(2x-4\right)\left(2x+4\right)}{\left(1-x\right)^2}.\frac{1-x}{3x-6}=\frac{\left(2x-4\right)\left(2x+4\right)}{\left(1-x\right)\left(3x-6\right)}\)
28 tháng 3 2020
\(\frac{4x^2-16}{1-2x+x^2}:\frac{3x-6}{1-x}\)
\(=\frac{4x^2-16}{1-2x+x^2}\cdot\frac{1-x}{3x-6}\)
\(=\frac{4\left(x^2-4\right)}{\left(1-x\right)^2}\cdot\frac{1-x}{3\left(x-2\right)}\)
\(=\frac{4\left(x-2\right)\left(x+2\right)}{\left(1-x\right)^2}\cdot\frac{1-x}{3\left(x-2\right)}\)
\(=\frac{4\left(x-2\right)\left(x+2\right)\left(1-x\right)}{\left(1-x\right)^2\cdot3\left(x-2\right)}\)
\(=\frac{4\left(x+2\right)}{3\left(1-x\right)}\)
U
15 tháng 3 2020
1,\(\frac{3}{2x+6}-\frac{x-6}{x\left(2x+6\right)}\)
=\(\frac{3x}{x\left(2x+6\right)}+\frac{x-6}{x\left(2x+6\right)}\)
=\(\frac{3x+x-6}{x\left(2x+6\right)}\)=\(\frac{4x-6}{x\left(2x+6\right)}=\frac{2\left(2x-3\right)}{x\left(2x+6\right)}\)
9 tháng 12 2019
\(\frac{3\left(x+1\right)}{x+2}-\frac{3x-6}{x^2-4}\)
\(=\frac{3\left(x+1\right)}{x+2}-\left(\frac{3x-6}{x^2-4}\right)\)
\(=\frac{3x^2-6x^2-12x+24}{x^3+2x^2-4x-8}\)
\(=\frac{3\left(x+2\right)\left(x-2\right)\left(x-2\right)}{\left(x+2\right)\left(x+2\right)\left(x-2\right)}\)
\(=\frac{3x-6}{x+2}\)
9 tháng 12 2019
\(\frac{x^2+4x+4}{1-x}.\frac{\left(1-x\right)^2}{3\left(x+2\right)^3}\)
\(=\frac{x^2+4x+4}{1-x}.\left[\frac{\left(1-x\right)^2}{3\left(x+2\right)^3}\right]\)
\(=\frac{x^4+2x^3-3x^2-4x+4}{-3x^4-15x^3-18x^2+12x+24}\)
\(=\frac{\left(x-1\right)\left(x-1\right)\left(x+2\right)\left(x+2\right)}{3\left(-x+1\right)\left(x+2\right)\left(x+2\right)\left(x+2\right)}\)
\(=\frac{-x+1}{3x+6}\)
DV
20 tháng 12 2016
a. \(=\frac{x+1}{2.\left(x+3\right)}+\frac{2x+3}{x.\left(x+3\right)}=\frac{x^2+x+4x+6}{2x.\left(x+3\right)}=\frac{x^2+5x+6}{2x.\left(x+3\right)}=\frac{\left(x+2\right).\left(x+3\right)}{2x.\left(x+3\right)}=\frac{x+2}{2x}\)
b. =\(\frac{2.\left(x+3\right)}{x.\left(3x-1\right)}.\frac{-\left(3x-1\right)}{x.\left(x+3\right)}=\frac{-2}{x^2}\)
Chắc chắn đúng, mik nhaaaaaa
AT
16 tháng 3 2020
a, \(\frac{4x+1}{2}-\frac{3x+2}{3}=\frac{12x+3}{6}-\frac{6x+4}{6}=\frac{12x+3-6x-4}{6}=\frac{6x-1}{6}\)
b, \(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}=\frac{x+3}{\left(x-1\right)\left(x+2\right)}-\frac{1}{x\left(x+1\right)}\)
\(=\frac{x\left(x+3\right)}{x\left(x-1\right)\left(x+1\right)}-\frac{x-1}{x\left(x-1\right)\left(x+1\right)}\)
\(=\frac{x^2+3x-x+1}{x\left(x-1\right)\left(x+1\right)}=\frac{x^2+2x+1}{x\left(x-1\right)\left(x+1\right)}=\frac{\left(x+1\right)^2}{x\left(x-1\right)\left(x+1\right)}\)
\(=\frac{x+1}{x\left(x-1\right)}\)
16 tháng 3 2020
\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
\(=\frac{12x+3}{6}-\frac{6x+4}{6}=\frac{6x-1}{6}\)
tương tự đến hết nha a hay cj gì đps !
15 tháng 12 2017
a) \(\frac{5x+10}{4x-8}.\frac{4-2x}{x+2}=\frac{5\left(x+2\right)}{4\left(x-2\right)}.\frac{2\left(2-x\right)}{x+2}=\frac{-5}{2}\)
b) \(\frac{1-4x^2}{x^2+4x}:\frac{2-4x}{3x}=\frac{\left(1-2x\right)\left(1+2x\right)}{x\left(x+4\right)}.\frac{3x}{2\left(1-2x\right)}=\frac{3\left(1+2x\right)}{2\left(x+4\right)}=\frac{3+6x}{2x+8}\)
SN
6 tháng 11 2016
mk ko biết làm
xin lỗi bn nhae
xin lỗi vì đã ko giúp được bn
chcus bn học gioi!
nhae@@@
Bài làm
\(\frac{x^2}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{x+2}\)( có sửa )
ĐKXĐ : \(\hept{\begin{cases}x\ne0\\x\ne\pm2\\x\ne4\end{cases}}\)
\(=\frac{x^2}{x\left(x^2-4\right)}-\frac{6}{3x-6}+\frac{1}{x+2}\)
\(=\frac{x}{x^2-4}-\frac{6}{3\left(x-2\right)}+\frac{1}{x+2}\)
\(=\frac{x}{\left(x-2\right)\left(x+2\right)}-\frac{2}{x-2}+\frac{1}{x+2}\)
\(=\frac{x}{\left(x-2\right)\left(x+2\right)}-\frac{2\left(x+2\right)}{\left(x-2\right)\left(x+2\right)}+\frac{x-2}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x}{\left(x-2\right)\left(x+2\right)}-\frac{2x+4}{\left(x-2\right)\left(x+2\right)}+\frac{x-2}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{x-2x-4+x-2}{\left(x-2\right)\left(x+2\right)}\)
\(=\frac{-6}{\left(x-2\right)\left(x+2\right)}\)
Nếu mình sửa đề sai thì ib mình làm lại cho