80-(4.5^2-3x2^3)
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80 − ( 4.\(5^2\)− 3.\(2^3\) )
= 80 − ( 4.25 − 3.8 )
= 80 − ( 100 − 24 )
= 80 − 100 + 24
= − 20 + 24
= 4
80 - (4.52 - 3.23)
= 80 - (4.25 - 3.8)
= 80 - (100 - 24)
= 80 - 76
= 4
80 - (4.52 - 3.23)
= 80 - (4.25 - 3.8)
= 80 - (100 - 24)
= 80 - 76
= 4
\(80-\left(4.5^2-3.2^3\right)=2^{10}-\left(x-4\right)\\ 80-\left(4.25-3.8\right)=1024-\left(x-4\right)\\ 80-\left(100-24\right)=1024-\left(x-4\right)\\ 80-76=1024-\left(x-4\right)\\ 4=1024-\left(x-4\right)\\ x-4=1024-4\\ x-4=1024-4\\ x-4=1020\\ x=1020+4\\ x=1024\)
80-(4.52-3.23)=210-(x-4)
80-(4.25-3.8)=1024-(x-4)
80-(100-24)=1024-(x-4)
80-76=1024-(x-4)
4=1024-(x-4)
4-1024= x-4
1020= x-4
1020+4=x
1024=x
\(80-\left(4.5^2-3.3.2^3\right)\)
\(\Rightarrow80-\left(2^2.5^2-3^2.2^3\right)\)
\(\Rightarrow80-\left(100-72\right)\)
\(\Rightarrow80-28\)
\(\Rightarrow52\)
\(80-\left(2^2.5^2-3^2.2^3\right)\)
\(80-\left(100-72\right)\)
\(80-28=52\)
\(80-\left(4.5^2-3.2^3\right)=2^{10}-\left(x-4\right)\) )
=> \(80-\left[2^2\left(5^2-3.2\right)\right]=2^{10}-x+4\)
=> \(80-\left[2^2\left(25-6\right)\right]=2^{10}-x+4\)
=> \(80-\left(4.19\right)=2^{10}-x+4\)
=> \(80-76-4=2^{10}-x\)
=> \(2^{10}-x=0\)
=> \(x=1024\)
90-[4.52-3.23]=210-(x-40
90-[100-24]=210-(x-4)
90-76=210-(x-4)
14=1024-(x-4)
x-4=1024-14
x-4=1010
x=1010+4
x=1014