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29 tháng 8 2020

Bài làm:

Ta có: \(\frac{12^6.5^2-2^{10}.3^5.5^2}{12^6.10-2^{12}.3^8}\)

\(=\frac{2^{12}.3^6.5^2-2^{10}.3^5.5^2}{2^{13}.3^6.5-2^{12}.3^8}\)

\(=\frac{2^{10}.3^5.5^2.\left(2^2.3-1\right)}{2^{12}.3^6.\left(2.5-3^2\right)}\)

\(=\frac{5^2.11}{2^2.3}=\frac{275}{12}\)

12 tháng 6 2017

\(1,\)

\(\dfrac{45^2.3^8.10^5}{5^5.3^7.18^5}\)

\(=\dfrac{3^4.5^2.3^8.2^5.5^5}{5^5.3^7.2^5.3^{10}}\)

\(=\dfrac{3^{12}.2^5.5^7}{5^5.3^{17}.2^5}\)

\(=\dfrac{1.5^2}{3^5.1}\)

\(=\dfrac{25}{243}\)

\(2,\)

\(\dfrac{4^5.9^4+2.6^9}{2^{10}.3^8+6^8.20}\)

\(=\dfrac{2^{10}.3^8+2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

\(=\dfrac{2^{10}.3^8+2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

\(=\dfrac{2^{10}.3^8.4}{2^{10}.3^8.6}\)

\(=\dfrac{2^{12}.3^8}{2^{11}.3^9}\)

\(=\dfrac{2}{3}\)

\(3,\)

\(\dfrac{15.3^{11}+4.27^4}{9^7}\)

\(=\dfrac{3.5.3^{11}+2^2.3^{12}}{3^{14}}\)

\(=\dfrac{5.3^{12}+2^2.3^{12}}{3^{14}}\)

\(=\dfrac{3^{12}\left(5+2^2\right)}{3^{14}}\)

\(=\dfrac{3^{12}.9}{3^{14}}\)

\(=\dfrac{3^{14}}{3^{14}}\)

\(=1\)

\(4,\)

\(\dfrac{4^7.2^8}{3.2^{15}.16^2-5^2\left(2^{10}\right)^2}\)

\(=\dfrac{2^{22}}{3.2^{23}-5^2.2^{20}}\)

\(=\dfrac{2^{22}}{2^{20}.\left(-1\right)}\)

\(=\dfrac{2^{22}}{-2^{20}}\)

\(=-4\)

* Mấy bài còn lại tương tự đấy bạn tự làm đi

Mình mỏi tay lắm rồi

12 tháng 6 2017

P/s:khuyến khích tự làm,chỉ làm mẫu 1 câu:

1)\(\dfrac{45^2.3^8.10^5}{5^5.3^7.18^5}=\dfrac{\left(5.9\right)^2.3.3^7.\left(2.5\right)^5}{5^5.3^7.\left(2.9\right)^5}\)\(=\dfrac{5^2.9^2.3.3^7.2^5.5^5}{5^5.3^7.2^5.9^5}\)\(=\dfrac{5^2.9^2.3.1.1.1}{1.1.1.9^5}\)\(=\dfrac{5^2.9^2.3}{9^5}=\dfrac{5^2.9^2.3}{9^2.9^3}=\dfrac{5^2.3}{9^3}=\dfrac{75}{729}=\dfrac{25}{243}\)

15 tháng 9 2016

a. - \(\frac{-1}{2}\)

b. \(\frac{238}{3}\)

15 tháng 9 2016

Kotori Minami bạn có thể giải chi tiết ra duoc ko

18 tháng 8 2023

a) \(\left(\dfrac{3}{4}\right)^{-2}\cdot3^2\cdot12^0=16\)

b) \(\left(\dfrac{1}{12}\right)^{-1}\cdot\left(\dfrac{2}{3}\right)^{-2}=27\)

c) \(\left(2^{-2}\cdot5^2\right)^{-2}:\left(5\cdot5^{-5}\right)=16\)

21 tháng 10 2018

ban nao co chuyen shin ko cho minh muon minh giai cho 10 bai nhu the i love pac pac

28 tháng 1 2019

\(A=\frac{2^{12}.3^4-4^5.9^2}{\left(2^2.3\right)^6+8^4.3^5}\)

\(A=\frac{2^{12}.3^4-2^{10}.3^4}{2^{12}.3^6+2^{12}.3^5}\)

\(A=\frac{2^{10}.3^4\left(2^2-1\right)}{2^{10}.3^4\left(2^2.3^2+2^2.3\right)}\)

\(A=\frac{2^2-1}{2^2.3^2+2^2.3}\)

\(A=\frac{4-1}{36+12}\)

\(A=\frac{3}{48}=\frac{1}{16}\)

27 tháng 9 2016
  • \(\frac{4^6.3^4.9^5}{6^{12}}=\frac{\left(2^2\right)^6.3^4.\left(3^2\right)^5}{\left(2.3\right)^{12}}=\frac{2^{12}.3^4.3^{10}}{2^{12}.3^{12}}=\frac{2^{12}.3^{14}}{2^{12}.3^{12}}=3^2=9\)
  • ​​\(\frac{3^{10}.11+9^5.5}{3^9.2^4}=\frac{3^{10}.11+\left(3^2\right)^5.5}{3^9.16}=\frac{3^{10}.11+3^{10}.5}{3^9.16}=\frac{3^{10}.\left(11+5\right)}{3^9.16}=\frac{3^{10}.16}{3^9.16}=3\)
  • 2100 - 299 - 298 - ... - 22 - 2

= 2100 - (299 + 298 + ... + 22 + 2)

Đặt A = 299 + 298 + ... + 22 + 2

2A = 2100 + 299 + ... + 23 + 22

2A - A = (2100 + 299 + ... + 23 + 22) - (299 + 298 + ... + 22 + 2)

A = 2100 - 2

Ta có:

2100 - 299 - 298 - ... - 22 - 2

= 2100 - (2100 - 2)

= 2100 - 2100 + 2

= 0 + 2

= 2

  • 38 : 36 + (22)4 : 29

= 32 + 28 : 29

\(=9+\frac{1}{2}\)

\(=\frac{18}{2}+\frac{1}{2}=\frac{19}{2}\)