Tính
5^4×20^4\25^5×45
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\(5\dfrac{5}{11}-\left(2\dfrac{3}{5}\cdot4\dfrac{6}{11}\right)=\dfrac{60}{11}-\left(\dfrac{13}{5}\cdot\dfrac{50}{11}\right)=\dfrac{60}{11}-\dfrac{130}{11}=-\dfrac{70}{11}\)
a: \(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}\)
b: \(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{5^{30}\cdot3^{20}}{3^{15}\cdot5^{30}}=3^5\)
a)\(\dfrac{8^{20}+4^{20}}{4^{25}+64^5}=\dfrac{2^{60}+2^{40}}{2^{50}+2^{30}}=\dfrac{2^{40}\left(2^{20}+1\right)}{2^{30}\left(2^{20}+1\right)}=2^{10}=1024\)
b)\(\dfrac{45^{10}\cdot5^{20}}{75^{15}}=\dfrac{9^{10}\cdot5^{30}}{3^{15}\cdot5^{30}}=\dfrac{3^{20}}{3^{15}}=3^5=243\)
Sai ở chỗ:<=> 4-9/2 = 5-9/2 <=> 4=5
thế này mới đúng!
\(\left(4-\frac{9}{2}\right)^2=\left(5-\frac{9}{2}\right)^2\Leftrightarrow\left(4-\frac{9}{2}\right)\left(4-\frac{9}{2}\right)=\left(5-\frac{9}{2}\right)\left(5-\frac{9}{2}\right)\)
\(\dfrac{5}{6}-\dfrac{1}{2}\times\dfrac{3}{4}\)
\(=\dfrac{5}{6}-\dfrac{3}{8}\)
\(=\dfrac{20}{24}-\dfrac{9}{24}\)
\(=\dfrac{11}{24}\)
\(\dfrac{5}{6}+\dfrac{1}{2}:\dfrac{3}{4}\)
\(=\dfrac{5}{6}+\dfrac{1}{2}\times\dfrac{4}{3}\)
\(=\dfrac{5}{6}+\dfrac{2}{3}\)
\(=\dfrac{5}{6}+\dfrac{4}{6}\)
\(=\dfrac{9}{6}=\dfrac{3}{2}\)
5^4*20^4/25^5*45=5^4 *5^4*4^4/25^4*25*45=4^4/25*45=256/1125