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18 tháng 8 2020

1/2-(2/3×x-1/3)=2/3

(2/3×x-1/3)=1/2-1/3

(2/3×x-1/3)=1/6

2/3×x=1/6+1/3

2/3×x=1/2

x=1/2:2/3

x=3/4

vậy x=3/4

3/x+5=15%

3/x+5=3/20

3/x=3/20-5

3/x=-97/20

3×20=x×-97

60=x×-97

x×-97=60

x=60:-97

x=-60/97

vậy x=-60/97

Ta có:\(\frac{1}{2}-\left(\frac{2}{3}\times x-\frac{1}{3}\right)=\frac{2}{3}\Rightarrow\frac{2}{3}\times x-\frac{1}{3}=\frac{1}{2}-\frac{2}{3}\)

\(\Rightarrow\frac{2}{3}\times x-\frac{1}{3}=\frac{-1}{6}\)

\(\Rightarrow\frac{2}{3}\times x=\frac{-1}{6}+\frac{1}{3}\Rightarrow\frac{2}{3}\times x=\frac{1}{6}\Rightarrow x=\frac{1}{6}:\frac{2}{3}=\frac{1}{4}\)

Vậy x=1/4

Ta có:\(\frac{3}{x}+5=15\%\Rightarrow\frac{3}{x}=\frac{3}{20}-5\Rightarrow\frac{3}{x}=\frac{-97}{20}\Rightarrow x=\frac{3}{\frac{-97}{20}}=\frac{-60}{97}\)

Vậy x=-60/97

27 tháng 7 2023

1) \(2^3\times x-5^2\times x=2\times\left(5^2+2^2\right)-33\)

\(x\times\left(2^3-5^2\right)=2\times\left(25+4\right)-33\)

\(x\times\left(8-25\right)=2\times29-33\)

\(x\times-17=25\)

\(x=-\dfrac{25}{17}\)

2) \(15\div\left(x+2\right)=\left(3^3+3\right)\div1\)

\(15\div\left(x+2\right)=\left(27+3\right)\div1\)

\(15\div\left(x+2\right)=30\div1\)

\(15\div\left(x+2\right)=30\)

\(x+2=\dfrac{1}{2}\)

\(x=-\dfrac{3}{2}\)

3) \(20\div\left(x+1\right)=\left(5^2+1\right)\div13\)

\(20\div\left(x+1\right)=\left(25+1\right)\div13\)

\(20\div\left(x+1\right)=26\div13\)

\(20\div\left(x+1\right)=2\)

\(x+1=20\div2\)

\(x+1=10\)

\(x=9\)

27 tháng 7 2023

4) \(320\div\left(x-1\right)=\left(5^3-5^2\right)\div4+15\)

\(320\div\left(x-1\right)=\left(125-25\right)\div4+15\)

\(320\div\left(x-1\right)=100\div4+15\)

\(320\div\left(x-1\right)=25+15\)

\(320\div\left(x-1\right)=40\)

\(x-1=8\)

\(x=9\)

5) \(240\div\left(x-5\right)=2^2\times5^2-20\)

\(240\div\left(x-5\right)=4\times25-20\)

\(240\div\left(x-5\right)=100-20\)

\(240\div\left(x-5\right)=80\)

\(x-5=30\)

\(x=35\)

6) \(70\div\left(x-3\right)=\left(3^4-1\right)\div4-10\)

\(70\div\left(x-3\right)=\left(81-1\right)\div4-10\)

\(70\div\left(x-3\right)=80\div4-10\)

\(70\div\left(x-3\right)=20-10\)

\(70\div\left(x-3\right)=10\)

\(x-3=7\)

\(x=10\)

4 tháng 10 2018

x=-36

x=11

x=100

x=14

4 tháng 10 2018

x=-36

x=11

x=100

x=14

17 tháng 10 2021

1: Ta có: \(20-2\left(x+4\right)=4\)

\(\Leftrightarrow2\left(x+4\right)=16\)

\(\Leftrightarrow x+4=8\)

hay x=4

5: Ta có: \(\left(x+1\right)^3=27\)

\(\Leftrightarrow x+1=3\)

hay x=2

c: Ta có: \(\dfrac{2}{5}\cdot\left[\left(\dfrac{3}{5}\right)^2:\left(-\dfrac{1}{5}\right)^2-7\right]\cdot\left(1000\right)^0\cdot\left|-\dfrac{11}{15}\right|\)

\(=\dfrac{2}{5}\cdot\left(\dfrac{9}{25}:\dfrac{1}{25}-7\right)\cdot1\cdot\dfrac{11}{15}\)

\(=\dfrac{2}{5}\cdot\dfrac{11}{15}\cdot2\)

\(=\dfrac{44}{75}\)

21 tháng 8 2021

Cảm ơn bạn lần nữa! vui

8 tháng 7 2018

1/ \(1+\frac{2}{x-1}+\frac{1}{x+3}=\frac{x^2+2x-7}{x^2+2x-3}\)

ĐKXĐ: \(\hept{\begin{cases}x-1\ne0\\x+3\ne0\end{cases}}\Leftrightarrow\hept{\begin{cases}x\ne1\\x\ne-3\end{cases}}\)

<=> \(1+\frac{2\left(x+3\right)+x-1}{\left(x-1\right)\left(x+3\right)}=\frac{x^2+2x-3-5}{x^2+2x-3}\)

<=> \(1+\frac{2x+6+x-1}{x^2+2x-3}=1-\frac{5}{x^2+2x-3}\)

<=> \(\frac{3x+5}{x^2+2x-3}+\frac{5}{x^2+2x-3}=1-1\)

<=> \(\frac{3x+5}{x^2+2x-3}+\frac{5}{x^2+2x-3}=0\)

<=> \(\frac{3x+10}{x^2+2x-3}=0\)

<=> \(3x+10=0\)

<=> \(x=-\frac{10}{3}\)

29 tháng 4 2022

4/15 +1/2=23/30
51/9 - 2/3=5
3/4 x 15/26=45/104

7/3 : 5/14=98/15

29 tháng 4 2022

4/15 + 1/2

= 8/30 + 15/30

= 23/30

51/9 - 2/3

= 51/9 - 6/9

= 45/9

= 5

3/4 × 15/26

= 45/104

7/3 : 5/14

= 7/3 × 14/5

= 98/15

10 tháng 8 2021

\(2^3x+5^2x=2.\left(5^2+2^3\right)-33\)

\(8x+25x=2.\left(25+8\right)-33\)

\(8x+25x=2.33-33\)

\(8x+25x=66-33\)

\(8x+25x=33\)

\(x+\left(8+25\right)=33\)

\(x+33=33\)

\(x=0\)

10 tháng 8 2021

\(15:\left(x+2\right)=\left(3^3+3\right):10\)

\(15:\left(x+2\right)=\left(27+3\right):10\)

\(15:\left(x+2\right)=30:10\)

\(15:\left(x+2\right)=3\)

\(x+2=15:3\)

\(x+2=5\)

\(x=3\)

VC
31 tháng 7 2019

1)\(\frac{252}{x}=\frac{84}{97}\Rightarrow\)\(\frac{84}{97}=\frac{252}{291}\Rightarrow x=291\)

6) \(\frac{y}{15}=\frac{2}{5}\Rightarrow\frac{2}{5}=\frac{6}{15}\Rightarrow x=6\)

a: \(\dfrac{-8}{3}\cdot\dfrac{15}{24}=\dfrac{-8}{24}\cdot\dfrac{15}{3}=\dfrac{-1}{3}\cdot5=-\dfrac{5}{3}\)

b: \(=\dfrac{3}{4}\cdot\dfrac{1}{-9}=\dfrac{-1}{12}\)

c: \(x=-\dfrac{7}{6}+\dfrac{5}{8}=-\dfrac{13}{24}\)

d: \(x=-\dfrac{14}{25}-\dfrac{3}{4}=\dfrac{-56-75}{100}=\dfrac{-131}{100}\)