tim x
3/4x=1
4/7x=9/8-0,125
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a/
3/4 . x = 1
=> x= 1: 3/4 = 4/3
b/
4/7 .x = 9/8 -0,125 = 9/8 -1/8 = 1
=> x= 1 : 4/7 = 7/4
a/ 3/4x=1
x=1:3/4
x=4/3
b/ 4/7x=9/8-0,125
4/7x=1
x=1:4/7
x=7/4
Lời giải:
a)
\(\frac{3}{4}x=1\)
\(x=1:\frac{3}{4}=1.\frac{4}{3}=\frac{4}{3}\)
b)
\(\frac{4}{7}x=\frac{9}{8}-0,125\)
\(\frac{4}{7}x=1\)
\(x=1:\frac{4}{7}\)
\(x=\frac{7}{4}\)
a) 3/4x = 1
x = 1 : 3/4
x = 4/3
b) 4/7x = 9/8 - 0,125
4/7x = 1
x = 1 : 4/7
x = 7/4
Mik ko ghi đề
Câu a)x=41×13 x=533
Câu b)x=1428:14 x=102
Câu c)4x=0×17
4x=0
x=0+4
x=4Mik mỏi tay ko viết nữa sorry
a)x:13=41
x=41.13
x=533
Vậy x=533
b)1428:x=14
x=1428:14
x=102
Vậy x=102
c)4x:17=0
4x=0.17
x=0:4
x=0
Vậy x=0
d)7x-8=713
7x=713+8
7x=721
x=721:7
x=103
Vậy x=103
a, x : 13 = 41
=> x = 41 x 13
=> x = 533
b, 1428 : x = 14
=> x = 1428 : 14
=> x = 102
c, 4x : 17 = 0
=> 4x = 0 x 17
=> x = 0 : 4
=> x = 0
d, 7x - 8 = 713
=> 7x = 713 + 8
=> x = 721 :7
=> x = 103
e, 8( x - 3 ) = 0
( x - 3 ) = 8 : 0
x - 3 = 0
x = 0 + 3
x = 3
g, 0 : x = 0
=> x = 0 : 0
=> x = 0
a, x : 13 = 41
=> x = 41 x 13
=> x = 533
b, 1428 : x = 14
=> x = 1428 : 14
=> x = 102
c, 4x : 17 = 0
=> 4x = 0 x 17
=> x = 0 : 4
=> x = 0
d, 7x - 8 = 713
=> 7x = 713 + 8
=> x = 721 :7
=> x = 103
e, 8( x - 3 ) = 0
( x - 3 ) = 8 : 0
x - 3 = 0
x = 0 + 3
x = 3
g, 0 : x = 0
=> x = 0 : 0
=> x = 0
a: \(x^2\left(x-3\right)-4x+12\)
\(=x^2\left(x-3\right)-4\left(x-3\right)\)
\(=\left(x-3\right)\left(x-2\right)\left(x+2\right)\)
b: \(2a\left(x+y\right)+x+y=\left(x+y\right)\left(2a+1\right)\)
c: \(6x^2-12x-7x+14\)
\(=6x\left(x-2\right)-7\left(x-2\right)\)
\(=\left(x-2\right)\left(6x-7\right)\)
3/ 4x=1 <=>x=1/4
4/7x=9/8-0,125 <=>7x=1<=>x=1/7
3/4x=1
<=>x=4/3
4/7x=9/8-0,125
<=>4/7x=9/8-1/8=8/8=1
<=>x=7/4