Rút gọn:a)5100-10/8160-16 ; b)952+8/2142+18
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a) Ta có: \(A=\left(4-x\right)\left(16+4x+x^2\right)-\left(4-x\right)^3\)
\(=64-x^3+\left(x-4\right)^3\)
\(=64-x^3+x^3-12x^2+48x-64\)
\(=-12x^2+48x\)
b) Ta có: \(B=\left(3x+2\right)\left(9x^2-6x+4\right)-\left(3x-2\right)\left(9x^2+6x+4\right)\)
\(=27x^3+8-27x^3+8\)
=16
c) Ta có: \(C=\left(x+1\right)\left(x^2-x+1\right)-x\left(x+1\right)^2\)
\(=x^3+1-x\left(x^2+2x+1\right)\)
\(=x^3+1-x^3-2x^2-x\)
\(=-2x^2-x+1\)
2A=2+22+23+24+...+211
2A—A=(2+22+23+24+....+211)—(1+2+22+23+...+210)
A=211—1
Ta có A = 2A - A
= \(2\left(1+2+2^2+2^3+...+2^{10}\right)\)- \(\left(1+2+2^2+2^3+....+2^{10}\right)\)
=\(2+2^2+2^3+2^4+.....+2^{11}\)\(-1-2-2^2-2^3-...-2^{10}\)
=\(2^{11}-1\)(Các số còn lại đã trừ hết cho nhau)
\(A=x-4-\sqrt{x^4-8x^2+16}=x-4-\sqrt{[\left(x-2\right)\left(x+2\right)]^2}\)
\(A=x-4-\left(x-2\right)\left(x+2\right)=x-4-\left(x^2-4\right)=-x^2+x\)
\(B=\dfrac{\left(\sqrt{a}-\sqrt{b}\right)^2}{\sqrt{a}-\sqrt{b}}.\left(\sqrt{a}+\sqrt{b}\right)=a-b\)
\(\left(x^2-2\right)\left(-x+3\right)\)
\(=-x^3+3x^2+2x-6\)
\(A=\dfrac{1}{2}sin4x-\dfrac{1}{2}sin2x+\dfrac{1}{2}sin12x+\dfrac{1}{2}sin2x\)
\(=\dfrac{1}{2}sin4x+\dfrac{1}{2}sin12x=sin8x.cos4x\)
\(B=\dfrac{1}{2}cos5x+\dfrac{1}{2}cos3x+\dfrac{1}{2}cosx-\dfrac{1}{2}cos5x\)
\(=\dfrac{1}{2}cos3x+\dfrac{1}{2}cosx=cos2x.cosx\)
Với `x >= 0,x ne 1` có:
`A=[10\sqrt{x}]/[(\sqrt{x}-1)(\sqrt{x}+4)]-[2\sqrt{x}-3]/[\sqrt{x}+4]-[\sqrt{x}+1]/[\sqrt{x}-1]`
`A=[10\sqrt{x}-(2\sqrt{x}-3)(\sqrt{x}-1)-(\sqrt{x}+1)(\sqrt{x}+4)]/[(\sqrt{x}-1)(\sqrt{x}+4)]`
`A=[10\sqrt{x}-2x+2\sqrt{x}+3\sqrt{x}-3-x-4\sqrt{x}-\sqrt{x}-4]/[(\sqrt{x}-1)(\sqrt{x}+4)]`
`A=[-3x+10\sqrt{x}-7]/[(\sqrt{x}-1)(\sqrt{x}+4)]`
`A=[(\sqrt{x}-1)(-3\sqrt{x}-7)]/[(\sqrt{x}-1)(\sqrt{x}+4)]`
`A=[-3\sqrt{x}-7]/[\sqrt{x}+4]`
3A=1.2.3+2.3.(4-1)+3.4.(5-2)+............+2015.2016.(2017-2014)
3A=1.2.3+2.3.4-1.2.3+3.4.5-2.3.4+.............+2015.2016.2017-2014.2015.2016
3A=2015.2016.2017
A=2015.2016.2017:3
A=2015.672.2017
\(A=\dfrac{\sqrt{3}\left(\sqrt{3}-1\right)}{\sqrt{3}-1}=\sqrt{3}\)
a.\(\frac{5100-10}{8160-16}\)= \(\frac{5090}{8144}\) = \(\frac{5}{8}\)
b.\(\frac{952+8}{2142+18}\) = \(\frac{960}{2160}\) = \(\frac{4}{9}\)
Chúc bạn học tốt!