\(\frac{3}{5.22}+\frac{54}{44.65}+\frac{18}{65.72}\)
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\(\frac{\frac{3}{67}.\left(17\frac{21}{56}-13\frac{21}{45}\right):\left(\frac{3}{5.22}+\frac{54}{44.65}+\frac{18}{65.72}\right)}{29^3:100-29^3:0,47}\)
\(=\frac{\frac{3}{67}\left(\frac{139}{8}-\frac{202}{15}\right):\left(\frac{3}{110}+\frac{54}{2860}+\frac{18}{4680}\right)}{29^3.\frac{1}{100}-29^3.\frac{47}{100}}\)
\(=\frac{\frac{3}{67}.\frac{469}{120}:\frac{1}{20}}{29^3\left(\frac{1}{100}-\frac{47}{100}\right)}\)
\(=\frac{\frac{7}{40}.20}{29^3.\left(-\frac{23}{50}\right)}\).
\(=\frac{\frac{7}{2}}{-11218,94}\)
\(=-\frac{175}{560947}\)
\(\frac{1}{3}-\left(\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+\frac{1}{180}+\frac{1}{270}+\frac{1}{378}\right)\)
\(=\frac{1}{3}-\left(\frac{1}{3.6}+\frac{1}{6.9}+\frac{1}{9.12}+\frac{1}{12.15}+\frac{1}{15.18}+\frac{1}{18.21}\right)\)
\(=\frac{1}{3}-\left(\frac{1}{3}-\frac{1}{21}\right)\)
\(=\frac{1}{3}-\frac{1}{3}+\frac{1}{21}=\frac{1}{21}\)
\(\frac{3}{5.22}+\frac{54}{44.65}+\frac{18}{65.72}=\frac{3}{110}+\frac{54}{2860}+\frac{18}{4680}=\frac{3}{65}+\frac{1}{260}=\frac{1}{20}\)