-2x+3.{12-2[3x-(20+2x)-4x]+1}=45
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-2x+3{12-2[3x-20-2x-4x]+1}=45
-2x+3[12-2(-3x-20)+1]=45
-2x+3(12+6x+40+1)=45
16x+159=45
16x=-114
x=-7,125
\(\Leftrightarrow-2x+3\cdot\left\{12-2\left[3x-20-2x-4x\right]+1\right\}=45\)
\(\Leftrightarrow-2x+3\cdot\left\{12-2\cdot\left(-3x-20\right)+1\right\}=45\)
=>-2x+3(11+6x+40)=45
=>-2x+153+18x=45
=>16x=45-153=-108
hay x=-6,75
\(-2x+3.\left\{12-2.\left[3x-\left(20+2x\right)-4x+1\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12-2\left[3x-20-2x-4x+1\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12-2.\left[-3x-19\right]\right\}=45\)
\(\Leftrightarrow-2x+3.\left\{12+6x+38\right\}=45\)
\(\Leftrightarrow-2x+36+18x+114=45\)
\(\Leftrightarrow16x+150=45\Leftrightarrow16x=-105\Leftrightarrow x=\frac{-105}{16}\)
mình giúp rùi đó nhớ k mk nhé ....
= -2x + 3[12-2(3x-20-2x-4x+1)]=45
= -2x +3[12-2(-3x-19)]=45
= -2x+3(12+6x+38)=45
= -2x+3(6x+50)=45
=-2x+18x+150=45
=16x=-105
=>x=-105/16
Ta có :-2x + 3x . { 12-2.[ 3.x-(20+2.x) - 4.x ] + 1 } = 45
<=>-2.x +3.x. [ 12-2 .( 3.x - 20 - 2.x - 4.x )+1 ) = 45
<=> -2.x + 3.x . [ 12- 2 ( -3.x -20 ) + 1 ] = 45
<=> -2.x + 3.x . ( 12 + 6.x + 40 + 1 ) = 45
<=>-2.x + 3.x . ( 53 + 6.x ) = 45
<=> -2.x + 159.x + 18.x2 = 45
<=> 157 .x + 18.x2 = 45
<=> 157.x + 18.x2 - 45 = 0
<=> 18.x2 - 5.x + 162.x - 45 = 0
<=> x. ( 18.x-5 ) + 9 .( 18.x-5) = 0
<=> ( 18.x-5 ) . ( x + 9 ) = 0
<=> \(\orbr{\begin{cases}18.x-5=0\\x+9=0\end{cases}}\)
<=> \(\orbr{\begin{cases}x=\frac{5}{18}\\x=-9\end{cases}}\)
Vậy x = { \(\frac{5}{18};-9\)}