Tìm x:
(X*3)*247=40755
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Bài 13 : Tìm x
30240 : x = 42
x = 30240 : 42
x = 720
X x 12 = 2412
X = 2412 : 12
X = 201
57316 : ( X - 8 ) = 623
X - 8 = 57316 : 623
X - 8 = 92
X = 92 + 8
X = 100
( X + 3 ) x 247 = 10755
X + 3 = 10755 : 247
X + 3 = 10755/247
X = 10755/247 - 3
X = 10014/247
X x 37 = 1135
X = 1135 : 37
X = 1135/37
25 x X = 9100
X = 9100 : 25
X = 364
Bài 13
1.720 2.201 3.100 4.162 5. 1135/37 6.364
bài 14
( 367*584+12345 ) * ( 3570: 357 - 10)
= ( 367*584+ 12345 ) * ( 10-10 )
= ( 367*584+12345 ) * 0
= 0
(367*584+12345)*(3570:357-10)
=(367*584+12345)*(10-10)
=(367*584+12345)*0
=0
\(3-\left(x-1\right)=2-2\left(x-3\right)\)
\(3-x+1=2-2x+6\)
\(4-x=8-2x\)
\(4-x-8+2x=0\)
\(x-4=0\)
\(x=4\)
3-(x-1)=2-2(x-3)=>3-2=x-1-2(x-3)=>1=x-1-2x+6
=>1=-x+5=>-x=1-5=-4=>x=4
Chúc bạn học tốt nhớ k cho mik nha.
a: =>x=1135:37=1135/37
b: =>3x=165
hay x=55
c: =>x-8=92
hay x=100
\(a,x=1135:37=30\left(dư.27\right)\\ b,x\times3=40755:247=165\\ x=165:3=55\\ c,x-8=57316:623=92\\ x=92+8=100\)
\(\left(x-1\right)^3-\left(\dfrac{2}{2023}-\dfrac{7}{247}+\dfrac{1}{8}\right)=\dfrac{7}{247}-\dfrac{2}{2023}\)
\(\Rightarrow\left(x-1\right)^3-\dfrac{2}{2023}+\dfrac{7}{247}-\dfrac{1}{8}=\dfrac{7}{247}-\dfrac{2}{2023}\)
\(\Rightarrow\left(x-1\right)^3=\dfrac{7}{247}-\dfrac{7}{247}-\dfrac{2}{2023}+\dfrac{2}{2023}+\dfrac{1}{8}\)
\(\Rightarrow\left(x-1\right)^3=\dfrac{1}{8}\)
\(\Rightarrow\left(x-1\right)^3=\left(\dfrac{1}{2}\right)^3\)
\(\Rightarrow x-1=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}+1\)
\(\Rightarrow x=\dfrac{3}{2}\)
Lời gải:
$(x-1)^3=\frac{7}{247}-\frac{2}{2023}+\frac{2}{2023}-\frac{7}{247}+\frac{1}{8}=\frac{1}{8}$
$x-1=\frac{1}{2}$
$x=\frac{1}{2}+1=\frac{3}{2}$
Ko biết ##########################################################
a) n = 32 x (132 - 247) - 132 x (32 - 247)
n = 32 x 132 - 32 x 247 - 132 x 32 - 132 x 247
n = 32 x (132 - 247 - 132) - 132 x 247
n = 32 x (-247) - 132 x 247
n = 32 x (-247) - (-132) x (-247)
n = 32 x (-247) + 132 x (-247)
n = (-247) x (32 + 132)
n = (-247) x 164
n = -40508
b) 3n + 6 \(⋮\)n + 1
=> (3n + 1) + 5 \(⋮\)n + 1
=> 5 \(⋮\)n + 1
=> n + 1 \(\in\)Ư(5) = {1;5}
=> n \(\in\){0;4}
a) \(15400:x=25\)
\(\Rightarrow x=15400:25\)
\(\Rightarrow x=616\)
b) \(\left(x+3\right):247=675:135\)
\(\Rightarrow\left(x+3\right):247=5\)
\(\Rightarrow x+3=5\times247\)
\(\Rightarrow x+3=1235\)
\(\Rightarrow x=1235-3\)
\(\Rightarrow x=1232\)
c) \(1224:\left(x-8\right)=24\)
\(\Rightarrow\left(x-8\right)=1224:24\)
\(\Rightarrow x-8=51\)
\(\Rightarrow x=51+8\)
\(\Rightarrow x=59\)
(x.3).247=40755
x.3=40755:247
x.3=165
x=165:3
x=55
Vậy x=55
(X*3)*247=40755
3x*247=40755
3x=40755:247
3x=165
x=165:3
x=55
k cho mk nha