CẦN GẤP!!!!!!!!!!!!!!!!!!!!
35.25+65.18+35.13+65.6
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a, 125+70+375+230
= (125+375)+(70+230)
= 500+300 = 800
b, 7 2 . 33 + 7 2 . 67
= 49.33+49.67 = 49.(33+67) = 49.100 = 4900
c, 35.11+65.18+35.13+65.6
= 35.(11+13)+65.(18+6) = 35.24+65.24 = 24.(35+65) = 24.100 = 2400
d, 490 – {[(128+22):3. 2 2 ] – 7}
= 490 – {[150:3.4] – 7}
= 490 – {[50.4] – 7}
= 490 – {200 – 7}
= 490 – 193 = 297
= 35 ( 13 + 15 ) + 65 ( 12 + 6 )
= 35 . 18 + 65 . 18
= 18 ( 35 + 65 )
= 18 . 100
= 1800
BÀI NÀY ĐẾN BỌN TIỂU HỌC CÒN LÀM ĐC
\(a.5\left(7+48:x\right)=45\)
\(7+48:x=45:5\)
\(7+48:x=9\)
\(48:x=9-7\)
\(48:x=2\)
\(x=48:2\)
\(x=24\)
\(b,49.50+13.49+49\)
\(=49\left(50+13+1\right)\)
\(=49.64\)
\(=3136\)
\(c,35.11+65.18+35.13+65.6\)
\(=35\left(11+13\right)+65\left(18+6\right)\)
\(=35.24+65.24\)
\(=24\left(35+65\right)\)
\(=24.100\)
\(=2400\)
a) 5.(7+48:x)=45
7+48:x =45:5
7+48:x= 9
48:x=9-7
48:x=2
x=48:2
x=24
b) 49.59+13.49+49
=49.(59+13+1)
=49.73
=3577
c) 35.11+65.18+35.13+65.6
=[35.11+35.13]+[65.18+65.6]
=[35.(11+13)]+[65.(18+6)]
=[35.44]+[65.24]
=1540+
\(A=\dfrac{\left(35+13\right)\left(35^2-35\cdot13+13^2\right)}{48}-35\cdot13\)
\(=35^2-2\cdot35\cdot13+13^2\)
\(=22^2=484\)
\(P=\frac{\left(35-13\right)\left(35^2+35.13+13^2\right)}{48}-35.13\)
\(=\frac{11\left(35^2+13^2+35.13\right)}{24}-\frac{24.35.13}{24}\)
\(=\frac{11.35^2+11.13^2+11.35.13-24.35.13}{24}\)
\(=\frac{11.35^2+11.13^2-13^2.24}{24}=\frac{11.35^2-13^3}{24}\)
Đến đay tính là ra
= \(\frac{35^3+13^3}{48}-35.13\)
=\(\frac{\left(35+13\right)\left(35^2-35.13+13^2\right)}{48}-35.13\)
=\(\frac{48.\left(35^2+13^2\right)-48.35.13-48.35.13}{48}\)
=352-2.35.13+132=(35-13)2=222=484
Vậy A = 484
35.25+65.18+35.13+65.6
= 35.25 + 35.13 + 65.18 + 65.6
= 35.( 25 + 13 ) + 65.(18+6)
= 35. 38 + 65 . 24
= 1330 + 1560
= 2890
35.25+65.18+35.13+65.6
= 35.(25+13) + 65.(18+6)
=35.38+65.24
=1330+1560
=2890.
#Hoc tot.