Question

[trâm kiều]

\(\sqrt{48.45}\)       Đưa thừa số ra ngoài dấu căn:

\(\sqrt{225.17}\)

\(\sqrt{a^3b^7}với\) \(a\ge0;b\ge0\)

\(\sqrt{x^5\left(x-3\right)^2}\) với \(x>0\)

Answer 1

[Nguyễn Hoàng Minh]

\(\sqrt{48\cdot45}=12\sqrt{15}\\ \sqrt{225\cdot17}=15\sqrt{17}\\ \sqrt{a^3b^7}=\left|ab^3\right|\sqrt{ab}=ab^3\sqrt{ab}\\ \sqrt{x^5\left(x-3\right)^2}=\left|x^2\left(x-3\right)\right|\sqrt{x}=x^2\left(x-3\right)\sqrt{x}\)

Answer 2

[Nguyễn Lê Phước Thịnh]

\(\sqrt{48\cdot45}=4\sqrt{3}\cdot3\sqrt{5}=12\sqrt{15}\)

\(\sqrt{225\cdot17}=15\sqrt{17}\)