tính bằng cách thuận tiện nhất :
a) 23*45 -23*35+23*90 b)636 / 6 - 36 / 6 c)11*607 -607
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TL:
8/15 x 5/6 = 40/90 = 4/9
41/20 x 3/4 = 123/80
(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43
HT
\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)
\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)
\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)
/HT\
\(\frac{11}{6}\times\frac{15}{23}-\frac{11}{6}\times\frac{7}{23}\)= \(\frac{11}{6}\times\left(\frac{15}{23}-\frac{7}{23}\right)\)
=\(\frac{11}{6}\times\frac{8}{23}\)
= \(\frac{44}{69}\)
a)Vì có nhiều số 52 nên .52x(3+7)=52x10=520
b)Vì có nhiều số 23 nên.23x(2+6+2)=23x10=230
c)Vì số 64 phép cuối ko có số nhân nên ta coi số đó là 1 nên. 64x7+64x2+64x1=64x(7+2+1)=64x10=640
d)Vì phép tính ở giữa có 2 số 48 cộng nên ta coi đó là 1 nên.48x(3+6+1)=48x10=480
nhé
a) 52 x 7 + 52 x 3
= 52 x ( 7 + 3 )
= 52 x 10
= 520
b) 23 x 2 + 6 x 23 + 23 x 2
= 23 x ( 2 + 6 + 2 )
= 23 x 10
= 230
c) 64 x 7 + 64 x 2 + 64
= 64 x 7 + 64 x 2 + 64 x 1
= 64 x ( 7 + 2 + 1 )
= 64 x 10
= 640
d) 48 x 3 + 48 + 48 x 6
= 48 x 3 + 48 x 1 + 48 x 6
= 48 x ( 3 + 1 + 6 )
= 48 x 10
= 480
a/64 x 23 + 37 x 23 - 23 + 6,24
= ( 64 + 37 - 1 ) x 23 + 6,24
= 100 x 23 + 6,24
= 2300 + 6,24
= 2306,24
b/33,76 + 19,52 + 6,24
= ( 33,76 + 6,24 ) + 19,52
= 40 + 19,52
= 59,52
c/\(\dfrac{38}{11}+\left(\dfrac{16}{13}+\dfrac{6}{11}\right)\)
\(=\dfrac{38}{11}+\dfrac{16}{13}+\dfrac{6}{11}\)
\(=\left(\dfrac{38}{11}+\dfrac{6}{11}\right)+\dfrac{16}{13}\)
\(=4+\dfrac{16}{13}\)
\(=\dfrac{52}{13}+\dfrac{16}{13}\)
\(=\dfrac{68}{13}\)
d/\(\dfrac{3}{4}:\dfrac{3}{5}-\dfrac{1}{5}\)
\(=\dfrac{3}{4}\times\dfrac{5}{3}-\dfrac{1}{5}\)
\(=\dfrac{5}{4}-\dfrac{1}{5}\)
\(=\dfrac{25}{20}-\dfrac{4}{20}\)
\(=\dfrac{21}{20}\)
#AvoidMe
a) 12 + 23 + 34 + 45 + 56 + 67 + 78 + 89
= ( 12 + 78 ) + ( 23 + 67 ) + ( 34 + 56 ) + ( 45 + 89 )
= 90 + 90 + 90 + 132
= 90 x 3 + 132
= 270 + 132
= 402
b) 125 x 6 x 7 x 8
= 750 x 7 x 8
= 5250 x 8
= 42000
c) ( 56 x 78 + 56 x 47 ) : 7
= 56 x ( 78 + 47 ) : 7
= 56 x 125 : 7
= 7000 : 7
= 1000
a) 12 + 23 + 34 + 45 + 56 + 67 + 78 + 89
= ( 12 + 78 ) + ( 23 + 67 ) + ( 34 + 56 ) + ( 45 + 89 )
= 90 + 90 + 90 + 132
= 90 x 3 + 132
= 270 + 132
= 402
b) 125 x 6 x 7 x 8
= 750 x 7 x 8
= 5250 x 8
= 42000
c) ( 56 x 78 + 56 x 47 ) : 7
= 56 x ( 78 + 47 ) : 7
= 56 x 125 : 7
= 7000 : 7
= 1000
\(a.=\left(\dfrac{4}{5}.\dfrac{5}{6}\right).\dfrac{2}{3}=\dfrac{4}{6}.\dfrac{2}{3}=\dfrac{4}{9}\)
\(b.\dfrac{4}{5}.\dfrac{3}{4}+\dfrac{5}{4}.\dfrac{3}{4}=\dfrac{3}{5}+\dfrac{15}{16}=\dfrac{123}{80}\)
\(c.\left(\dfrac{11}{23}+\dfrac{9}{23}\right)+\left(\dfrac{2}{23}+\dfrac{18}{23}\right)=\dfrac{20}{23}+\dfrac{20}{23}=\dfrac{40}{23}\)
\(d.\left(\dfrac{27}{12}-\dfrac{25}{36}\right)+\left(\dfrac{17}{6}-\dfrac{15}{6}\right)=\dfrac{14}{9}+\dfrac{1}{3}=\dfrac{17}{9}\)
a, = \(\frac{11}{21}\)x \(\left(\frac{7}{4}+\frac{5}{4}\right)\)
= \(\frac{11}{21}\)x 3
= \(\frac{33}{21}\)
b) = \(\left(\frac{23}{14}-\frac{9}{14}\right)\)x \(\frac{6}{13}\)
= 1 x \(\frac{6}{13}\)
= \(\frac{6}{13}\)
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a,17/23 + (1 - 17/23)
= 17/23 + 6/23
= 23/23 = 1
b,17/12 + 9/7 - (2/7 + 5 /12)
= (17/12 - 5/12) + (9/7 + 2/7)
= 1+1 = 2
c, 7/13 - ( 4/7 -6/13 )
= 7/13 - 4/7+ 6/13
= (7/13 + 6/13) -4/7
= 13/13 -4/7
= 1 -4/7 = 3/7
hok tốt✍️ ✍️
a) 17/23+(1-17/23)
=17/23+1-17/23
=1
b)17/12+9/7-(2/7+5/12)
=17/12+9/7-2/7-5/12
=1+1
=2
c)
7/13-(4/7-6/13)
=7/13-4/7+6/13
=1-4/7
=3/7
a) 23*45 -23*35+23*90
= 23* (45-35+90)
= 23*100
= 2300
b) 636/ 6 - 36/ 6
= 600/ 6
= 100
c) 11*607 -607
= 11*607 -607*1
= 607* (11 -1)
= 607*10
= 6070
a) 23 x 45 - 23 x 35 + 23 x 90
=23 x (45 - 35 + 90)
= 23 x 100
= 2300
b) 636 / 6 - 36 / 6
= (636 - 36) /6
= 600/6
=100
c) 11 x 607 - 607
= 607 x ( 11 - 1)
= 607 x 10
=6070