[7-x]-[25+7]=-25
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\(A)9-25=\left(7-x\right)-\left(25+7\right)\)
\(\Rightarrow9-25=7-x-25-7\)
\(\Rightarrow x=7-25-7-9+25\)
\(\Rightarrow x=\left(7-7\right)+\left(25-25\right)-9\)
\(\Rightarrow x=0+0-9\)
\(x=-9\)
\(B)x-\left(17-x\right)=x-7\)
\(\Rightarrow x-17+x=x-7\)
\(\Rightarrow2x-17=x-7\)
\(\Rightarrow x=-7+17\)
\(x=10\)
( 7 - x ) - ( 25 + 7 ) = - 25
( 7 - x ) - 32 = -25
( 7 - x ) = -25 + 32
( 7 - x ) = 7
x = 7 - 7
x = 0
( 7 - x ) - ( 25 + 7 ) = (- 25)
( 7 - x ) - 32 = -25
( 7 - x ) = -25 + 32
( 7 - x ) = 7
x = 7 - 7
x = 0
\(\left(7-x\right)-\left(25-7\right)=-25\)
\(=>\left(7-x\right)-18=-25\)
\(=>7x=\left(-25\right)+18\)
\(=>7x=-17\)
\(=>x=\dfrac{-17}{7}\)
3/25 x ( 15/7 - 2/7 ) + 3/7 x 1/25
= 3/25 x 13/7 + 3/7 x 1/25
= (3 x 13/7 + 3/7 ) x 1/25
= 42/7 x 1/25
= 6 x 1/25
= 6/25
\(\dfrac{3}{25}\times\dfrac{15}{7}+\dfrac{3}{7}\times\dfrac{1}{25}-\dfrac{2}{7}\times\dfrac{3}{25}\)
\(=\dfrac{3}{25}\times\left(\dfrac{15}{7}-\dfrac{2}{7}\right)+\dfrac{3}{7}\times\dfrac{1}{25}\)
\(=\dfrac{3}{25}\times\dfrac{13}{7}+\dfrac{3}{7}\times\dfrac{1}{25}\)
\(=\dfrac{3\times13}{25\times7}+\dfrac{3\times1}{7\times25}\)
\(=\dfrac{39}{175}+\dfrac{3}{175}\)
\(=\dfrac{39+3}{175}\)
\(=\dfrac{42}{175}\)
\(=\dfrac{6}{25}\)
b) |x-3|=7 - (-2)
|x-3| = 9
TH 1 : TH 2 :
x - 3 = 9 x - 3 = -9
x = 9 + 3 x = -9 + 3
x = 12 x = 6
c) (7-x)-(25+7)=-25
(7-x) = -25 + 25 - 7
(7-x) = - 7
x = -7 + 7
x = 0
1) 9-25=(7-x)-(25+7)
(7-x)-(25+7)=9-25
(7-x)-(25+7)=-16
(7-x)-32=-16
7-x=-16+32
7-x=16
x=7-16
x=-9
2) (27-514) -(486-73)+x=7
(27-514) -(486-73)+x=7
-487-413+x=7
-1011+x=7
x=7-(-1011)
x=7+1011
x=1018
3) 25+5+37-25+6-29-x=37
25+5+37-25+6-29-x=37
67-25+6-29-x=37
42+6-29-x=37
48-29-x=37
19-x=37
x=19-37
x=-18
4) 14+(-12)+x =10-/-15/+ /-3/
14+(-12)+x =10-15+3
14+(-12)+x =-5+3
14+(-12)+x =-2
2+x=-2
x=-2-2
x=-4
DỄ THẾ CŨNG HỎI
[7-x]-[25+7]=-25
7-x-25-7=-25
[7-7]-x=-25+25
0-x=0
x=0
Vậy: x=0
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