Question

[lại tuấn dũng]

n+11chia hết cho n-1

Answer 1

[ﾟ°☆Žυƙα☆° ﾟ]

\(n+11⋮n-1\)

\(\Leftrightarrow n+11-\left(n+1\right)⋮n-1\)

\(\Leftrightarrow10⋮n-1\)

Ta có bảng sau:

n-1	1	-1	2	-2	5	-5	10
n	2	0	3	-1	6	-4	11

n-1	-10
n	-9

vậy......

Answer 2

[Nguyễn Thị Hiền]

Ta co: n+11=n-1+12

ma n+11 chia het cho n-1 va n-1 chia het cho n-1

=>12 chia het cho n-1 =>n-1thuoc U(12)={1;2;3;4;6;12}

Ta xet: n-1=1=> n=2.

            n-1=2=> n=3.

            n-1=3=> n=4.

            n-1=4=> n=5.

            n-1=6=> n=7.

            n-1=12=> n=13.

Vay n thuoc {2;3;4;5;7;13}.