1 1/3x-(3/2)²=-0,75
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ok ko sao
2/3x : (-0.75)=1
2/3x=-0.75
2/3x=-3/4
x=-3/4:2/3
x=-9/8

\(\left|3x-1\right|-\dfrac{1}{2}=0,75=\dfrac{3}{4}\)
\(\left|3x-1\right|=\dfrac{3}{4}+\dfrac{1}{2}=\dfrac{5}{4}\)
⇔ \(\left[{}\begin{matrix}3x-1=\dfrac{5}{4}\\3x-1=-\dfrac{5}{4}\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}3x=\dfrac{9}{4}\\3x=-\dfrac{1}{4}\end{matrix}\right.\)
⇔ \(\left[{}\begin{matrix}x=\dfrac{3}{4}\\x=-\dfrac{1}{12}\end{matrix}\right.\)
|3x-1| -1/2= 0,75
=>|3x-1|= 0,75 -1/2
=>|3x-1|= -1/2
=> 3x-1= -1/2 hoặc 3x-1= 1/2
=> 3x= 1/2 hoặc 3x= 3/2
=>x=1/6 hoặc x=1/2

a: \(\Leftrightarrow x\cdot\dfrac{3}{5}=\dfrac{-1}{7}+\dfrac{1}{2}=\dfrac{1}{2}-\dfrac{1}{7}=\dfrac{5}{14}\)
\(\Leftrightarrow x=\dfrac{5}{14}:\dfrac{3}{5}=\dfrac{25}{42}\)
b: =>|3x-1|=2
\(\Leftrightarrow\left[{}\begin{matrix}3x-1=2\\3x-1=-2\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{1}{3}\end{matrix}\right.\)
c: \(\Leftrightarrow7\left(37-x\right)=3\left(x-13\right)\)
=>259-7x=3x-39
=>-10x=-298
hay x=29,8
d: =>x=3/4+2/3=9/12+8/12=17/12

Bài 2:
a: \(\left(3x-3\right)^2-\left(5x-3\right)^2=0\)
\(\Leftrightarrow\left(3x-3-5x+3\right)\left(3x-3+5x-3\right)=0\)
\(\Leftrightarrow-2x\left(8x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{3}{4}\end{matrix}\right.\)

a, \(\left(2x-1\right)^3=8\)
\(\Leftrightarrow\left(2x-1\right)^3=2^3\)
\(\Leftrightarrow2x-1=2\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)
b, \(\left(x-1\right)^x+2=\left(x-1\right)^x+4\)
\(\Leftrightarrow\left(x-1\right)^x+2-\left(x-1\right)^x-4=0\)
\(\Leftrightarrow-2\ne0\)=> vô nghiệm
c, \(3^x-1+5.3^{3x}-1=162\)
Đề sai.

\(1\frac{1}{3}x-\left(\frac{3}{2}\right)^2=-0,75\)
\(\frac{4}{3}x-\frac{9}{4}=-\frac{3}{4}\)
\(\frac{4}{3}x=-\frac{3}{4}+\frac{9}{4}\)
\(\frac{4}{3}x=\frac{3}{2}\)
\(x=\frac{3}{2}:\frac{4}{3}\)
\(x=\frac{3}{2}.\frac{3}{4}\)
\(x=\frac{9}{8}\)
Vậy \(x=\frac{9}{8}\)