375÷{32-[4+(5×3^2-42)]}-14
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\(375:\left\{32-\left[4+\left(5.32-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+\left(160-42\right)\right]\right\}-14\)
\(=375:\left\{32-\left[4+118\right]\right\}-14\)
\(=375:\left\{32-122\right\}-14\)
\(=375:\left(-90\right)-14\)
\(=\dfrac{-25}{6}-14\)
\(=\dfrac{-109}{6}\)
a) `27 .75 + 25.27 -150`
`=27 xx (75 + 25)-150`
`=27 xx 100-150`
`=2700-150`
`=2550`
b) `142-[50-(2^3 .10-2^3 .5)]`
`=142-[50-2^3 .(10-5)]`
`=142-(50-8 .5)`
`=142-(50-40)`
`=142-10`
`=132`
c) `375:{32-[4+(5.3^2-42)]}-14`
`=375:{32-[4+(45-42)]}-14`
`=375:[32-(4+3)]-14`
`=375: 25 -14`
`=15-14`
`=1`
a. 27 . 75 + 25 . 27 - 150
= 27. (75 + 25) - 150
= 27 . 100 - 150
= 2700 - 150
= 2550
b. 142 - [50 - (23.10 - 23.5)]
= 142 - [50 - (8 . 10 - 8 . 5)]
= 142 - {50 - [8 . (10 - 5)]}
= 142 - (50 - 40)
= 142 - 10
= 132
c. 375 : {32 – [ 4 + (5. 32 – 42)]} – 14
= 375 : {32 – [ 4 + (5. 9 – 42)]} – 14
= 375 : {32 – [ 4 + (45 – 42)]} – 14
= 375 : {32 – [ 4 + 3]} – 14
= 375 : {32 –7} – 14
= 375 : 25 - 14
= 15 - 14
= 1
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
a, 27.75 + 25.27 – 150
= 2025 + 675 – 150 = 2550
b, 142 – [50 – ( 2 3 .10 – 2 3 .5)]
= 142 – [50 – (80 – 40)] = 132
c, 375:{32 – [4+( 5 . 3 2 – 42]} – 14
= 375:{32 – [4+(45 – 42)]} – 14
= 375:(32 – 7) – 14 = 15 – 14 = 1
d, {210:[16+3.(6+3. 2 2 )]} – 3
= [210:(16+3.18)] – 3
= 210 : 70 – 3 = 3 – 3 = 0
Đề em ghi bị thiếu dấu ngoặc nhé, sửa lại đề và giải như vầy:
375 : {32 - [4 + (5.32 - 42)]} - 14
= 375 : {32 - [4 + (5.9 - 42)]} - 14
= 375 : {32 - [4 + (45 - 42)]} - 14
= 375 : [32 - (4 + 3)] - 14
= 375 : (32 - 7) - 14
= 375 : 25 - 14
= 15 - 14
= 1
a) \(142-\left[50-\left(2^3.10-2^3.5\right)\right]\)
= \(142-\left[50-\left(8.10-8.5\right)\right]\)
= \(142-\left[50-8.\left(10-5\right)\right]\)
= \(142-\left[50-8.5\right]\)
= \(142-\left[50-40\right]\)
= \(142-10\)
= \(132\)
b) \(375:\left\{32-\left[4+\left(5.3^2-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+\left(5.9-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+\left(45-42\right)\right]\right\}-14\)
= \(375:\left\{32-\left[4+3\right]\right\}-14\)
= \(375:\left\{32-7\right\}-14\)
= \(375:25-14\)
= \(15-14\)
= \(1\)
Chúc bạn học tốt !!!
a) 142 - [ 50 - ( 23 . 10 - 23 . 5 )]
= 142 - [ 50 - ( 8 . 10 - 8 . 5 )]
= 142 - [ 50 - ( 80 - 40 )]
= 142 - [ 50 - 40 ]
= 142 - 10
= 132
b) 375 : { 32 - [ 4 + ( 5 . 32 - 42 )]} - 14
= 375 : { 32 - [ 4 + ( 5 . 9 - 42 )]} - 14
= 375 : { 32 - [ 4 + ( 45 - 42 )]} - 14
= 375 : { 32 - [ 4 + 3 ]} - 14
= 375 : { 32 - 7 } - 14
= 375 : 25 - 14
= 15 - 14
= 1
Bài 1: Thực hiện các phép tính sau:
\(a)\)Chưa rỏ đề
\(b)\)\(5025\div5-25\div5\)
\(=\)\(1005-5\)
\(=\)\(1000\)
\(c)\)\(218-180\div2\div9\)
\(=\)\(218-10\)
\(=\)\(208\)
\(d)\)\(\left(328-8\right)\div32\)
\(=\)\(320\div32\)
\(=\)\(10\)
Bài 1:
a) ( Tôi không nhìn rõ đầu bài )
b) 5025 : 5 - 25 : 5
= ( 5025 - 25 ) : 5
= 5000 : 5
= 1000
c) 218 - 180 : 2 : 9
= 218 - 180 : ( 2 . 9 )
= 218 - 180 : 18
= 218 - 10
= 208
d) ( 328 - 8 ) : 32
= 320 : 32
= 10
\(375:\left\{32-\left[4+\left(5.3^2-42\right)\right]\right\}\)
\(=375:\left\{32-\left[4+\left(45-42\right)\right]\right\}=375:\left\{32-\left[4+3\right]\right\}=375:\left\{32-7\right\}\)
=\(375:25=15\)
\(375\div\left\{32-\left[4+\left(5\times3^2-42\right)\right]\right\}-14\)
\(=375\div\left\{32-\left[4+3\right]\right\}-14\)
\(=375\div\left\{32-7\right\}-14\)
\(=375\div25-14\)
\(=15-14\)
\(=1\)
Chúc bạn học tốt!!!
\(375\div\left\{32-\left[4+\left(5\times3^2-42\right)\right]\right\}-14\)
= 375 : { 32 - [ 4 + 3 ]} - 14
= 375 : { 32 - 7 } - 14
= 375 : 25 - 14
= 15 - 14
= 1
Chúc bạn học tốt!!!