24 : ( 6 - x ) = 8
25 . 5 x + 2 = 56
cac ban giup minh, minh can gap
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\(a,-12.\left(x-5\right)+7.\left(-x+3\right)=5\)
\(-12x+60-7x+21=5\)
\(-19x+81=5\)
\(-19x=5-81\)
\(-19x=-76\)
\(x=4\)
\(b,30.\left(x+2\right)-6.\left(x-5\right)-24.x=100\)
\(30x+60-6x+30-24x=100\)
\(0x+90=100\)
\(0x=100-90\)
\(0x=10\)
=> ko có giá trị nào thõa mãn x
+ ) \(\left(x-4\right)\left(6-x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-4=0\\6-x=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=4\\x=6\end{cases}}\)
+ ) \(\left(2x-1\right)^2=25\)
\(\left(2x-1\right)^2=5^2\)Hoặc \(\left(2x-1\right)^2=\left(-5\right)^2\)
\(\Rightarrow\orbr{\begin{cases}2x-1=5\\2x-1=-5\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\2x=-4\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=-2\end{cases}}}\)
+ ) \(\left(x\div6\right)^5=243\)
\(\left(x\div6\right)^5=3^5\)
\(\Rightarrow x\div6=3\)
\(\Leftrightarrow x=18\)
\(\left(2x-5\right)^3=8\)
\(\left(2x-5\right)^3=2^3\)
\(2x-5=2\)
\(2x=7\)
\(x=\frac{7}{2}\)
\(b,6⋮x-1\)
\(\Rightarrow x-1\inƯ6\left(\pm1,\pm2,\pm3\right)\)
+ x-1 =1 => x=2
+ x-1 =-1 =>x=0
+ x-1=2 =>x=3
+ x-1=-2 => x= -1
+ x-1 =3 =>x=4
+ x-1=-3 => x=-2
#Giải :
( 2x - 5 )3 = 8
( 2x - 5 )3 = 23
=> 2x - 5 = 2
2x = 7
x = 7/2
6 chia hết cho ( x - 1 )
=> (x - 1) € Ư (6)
Ư (6) = { 1 ; 2 ; 3 ; 6 }
Nếu x - 1 = 1 => x = 2
Nếu x - 1 = 2 => x = 3
Nếu x - 1 = 3 => x = 4
Nếu x - 1 = 6 => x = 7
[ P/S : € - thuộc ]
#By_Ami
\(6x+x=7^{34}\div7^{31}\)
\(x\left(6+1\right)=7^3\)
\(7x=7^3\)
\(x=7^2\)
\(x=49\)
6*x+x=7^34:7^31
x*(6+1)=7^3
x*7=7^3
x=7^3:7
x=7^2
x=49
Vậy x=49
( 7 . x - 11)\(^3\)=2\(^5\). 2\(^2\)+ 200
( 7 . x - 11)\(^3\)=32 . 4 + 200
( 7. x - 11)\(^3\)=328
( 7 . x - 1331) = 328
7 . x = 328 + 1331
7.x = 1659
x = 1659 : 7
x = 237
(7x-11)3=25.22+200
(7x-11)3=27+200
(7x-11)3=128+200
(7x-11)3=328
vô lí vì \(328\ne?^?\)được
vậy x\(\notin\varnothing\)
a)\(-2\left(x+6\right)+6\left(x-10\right)=8.\)
\(\Leftrightarrow-2x-12+6x-60=8\)
\(\Leftrightarrow4x=80\)
\(\Rightarrow x=20\)
b/ \(-4\left(2x+9\right)-\left(-8x+3\right)-\left(x+13\right)=0\)
\(\Leftrightarrow-8x-36+8x-3-x-13=0\)
\(\Leftrightarrow-x=52\)
\(\Rightarrow x=-52\)
c/\(7x\left(2+x\right)-7x\left(x+3\right)=14\)
\(\Leftrightarrow14x+7x^2-7x^2-21x=14\)
\(\Leftrightarrow-7x=14\)
\(\Rightarrow x=-2\)
24:(6-x)=8
6-x=24:8
6-x=3
x=6-3
x=3
#Châu's ngốc
a) \(24:\left(6-x\right)=8\)
\(6-x=24:8=3\)
\(x=6-3=3\)
Vậy x = 3
b) \(25\cdot5^{x+2}=5^6\)
\(5^2\cdot5^{x+2}=5^6\)
\(5^{x+2}=5^6:5^2=5^{6-2}=5^4\)
\(\Leftrightarrow x+2=4\)
\(x=4-2=2\)
Vậy x = 2