5x+3 + 5x = 126 x 53
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a) \(5^{x+3}+5^x=126\)
\(\Rightarrow5^x\cdot\left(5^3+1\right)=126\)
\(\Rightarrow5^x\cdot\left(125+1\right)=126\)
\(\Rightarrow5^x=\dfrac{126}{126}\)
\(\Rightarrow5^x=1\)
\(\Rightarrow5^x=5^0\)
\(\Rightarrow x=0\)
b) \(\dfrac{9-3x}{2}=\dfrac{5-2x}{3}\)
\(\Rightarrow\dfrac{3\cdot\left(9-3x\right)}{6}=\dfrac{2\cdot\left(5-2x\right)}{6}\)
\(\Rightarrow3\cdot\left(9-3x\right)=2\cdot\left(5-2x\right)\)
\(\Rightarrow27-9x=10-4x\)
\(\Rightarrow-4x+9x=27-10\)
\(\Rightarrow5x=17\)
\(\Rightarrow x=\dfrac{17}{5}\)
c) \(7-4\left(x+1\right)=5\)
\(\Rightarrow4\left(x+1\right)=7-5\)
\(\Rightarrow4\left(x+1\right)=2\)
\(\Rightarrow x+1=\dfrac{1}{2}\)
\(\Rightarrow x=\dfrac{1}{2}-1\)
\(\Rightarrow x=-\dfrac{1}{2}\)
A/ 15+(3-x)=-10
15+3-x=-10
18-x=-10
-x=-10-18=-8
Suy ra x= 8
a, 15 + (3-x) = -10
3-x = -10 - 15
3-x = -25
x = 3 - (-25)
x = -28
b, 11 - ( 53 + x ) = 97
53 + x = 11 - 97
53 + x = -86
x = -86 - 53
x = -139
c, 5x - (-25) = 35
5x =35 + ( -25)
5x = 10
x = 10 : 5
x = 2
Bài 1: Ta có: \(53^2-53\cdot6+3^2\)
\(=53^2-2\cdot53\cdot3+3^2\)
\(=\left(53-3\right)^2\)
\(=50^2=2500\)
Bài 2: Ta có: \(-x^2+x-33\)
\(=-\left(x^2-x+33\right)\)
\(=-\left(x^2-2\cdot x\cdot\frac{1}{2}+\frac{1}{4}+\frac{131}{4}\right)\)
\(=-\left(x-\frac{1}{2}\right)^2-\frac{131}{4}\)
Ta có: \(\left(x-\frac{1}{2}\right)^2\ge0\forall x\)
\(\Rightarrow-\left(x-\frac{1}{2}\right)^2\le0\forall x\)
\(\Rightarrow-\left(x-\frac{1}{2}\right)^2-\frac{131}{4}\le\frac{131}{4}< 0\forall x\)
hay \(-x^2+x-33< 0\forall x\)(đpcm)
Bài 3: Ta có: \(x^2+4x+33\)
\(=x^2+4x+4+29\)
\(=\left(x+2\right)^2+29\)
Ta có: \(\left(x+2\right)^2\ge0\forall x\)
\(\Rightarrow\left(x+2\right)^2+29\ge29>0\forall x\)
hay \(x^2+4x+33>0\forall x\)
Bài 4: Ta có: \(B=x^2+8x\)
\(=x^2+8x+16-16\)
\(=\left(x+4\right)^2-16\)
Ta có: \(\left(x+4\right)^2\ge0\forall x\)
\(\Rightarrow\left(x+4\right)^2-16\ge-16\forall x\)
Dấu '=' xảy ra khi x+4=0
hay x=-4
Vậy: Giá trị nhỏ nhất của biểu thức \(B=x^2+8x\) là -16 khi x=-4
Bài 5: Tìm x
Ta có: \(\left(5x+1\right)^2-\left(5x+3\right)\left(5x-3\right)=30\)
\(\Leftrightarrow25x^2+10x+1-\left(25x^2-9\right)-30=0\)
\(\Leftrightarrow25x^2+10x+1-25x^2+9-30=0\)
\(\Leftrightarrow10x-20=0\)
\(\Leftrightarrow10x=20\)
hay x=2
Vậy: x=2
Đáp án: B
25+5x= 5 6 : 5 3
25+5x=53
25+5x=125
5x=125-25
5x=100
x=100:5
x=20
Bài 1:
a: =42x53+47x42
=42x100
=4200
b: =1152-374-1152-65+374=-65
c: =(-1)+(-1)+...+(-1)+211
=211-105
=106
1/
a)5x – 20y=5(x-4y)
b) 5x.(x – 1) – 3x(x – 1)=2x(x-1)
c) x.(x+y) – 5x – 5y=c) x.(x+y) – 5(x+y)=(x-5)(x+y)
2/
a)x2 + xy + x = x(x+y+1)=77.(77+22+1)=77.100=7700
b) x . ( x – y ) + y . ( y – x )=(x-y)(x-y)=(x-y)2=(53-3)2=2500
3/
a) X + 5x2 = 0
⇒x(x+5)=0
⇒hoặc x=0
x+5=0⇒x=-5
b)x + 1 = ( x + 1 )2
⇒(x + 1)-( x + 1 )2 =0
⇒x(x+1)=0
⇒ hoặc x=0
hoặc x+1=0⇒x=-1
720 : [41 - (2x - 5)] = 8 . 5
=> 720 : [41 - (2x - 5)] = 40
=> 41 - (2x - 5) = 720 : 40
=> 41 - (2x - 5) = 18
=> 2x - 5 = 41 - 18
=> 2x - 5 = 23
=> 2x = 23 + 5
=> 2x = 28
=> x = 28 : 2
=> x = 14
Vậy x = 14
1 + 2 + 3 + 4 + ... + (x - 1) + x = 78
có x số hạng
=> (x + 1) . x : 2 = 78
=> (x + 1) . x = 78 . 2
=> (x + 1) . x = 156
=> (x + 1) . x = 13 . 12
=> x = 12
Vậy x = 12
=5 mu x nhan 5 mu 3+5 mu x=126 nhan 5 mu 3
=5 mu x+5 mu x=126(Cung chia 2 ve di 5 mu 3)
=(5 mu x)*2=126
=5 mu x=126:2
=5 mu x=63
=))
Dung thi nho k cho minh de ung ho minh nhe!Thanks!!!