25+5x-43=251
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a) Ta có: \(18-x=58-\left(-30\right)\)
\(\Leftrightarrow18-x=88\)
\(\Leftrightarrow x=18-88=-70\)
Vậy: x=-70
b) Ta có: \(x-27=\left(-43\right)-9\)
\(\Leftrightarrow x-27=-43-9\)
\(\Leftrightarrow x-27=-52\)
\(\Leftrightarrow x=-25\)
Vậy: x=-25
c) Ta có: \(169-\left(x+4\right)=69\)
\(\Leftrightarrow x+4=169-69\)
\(\Leftrightarrow x+4=100\)
\(\Leftrightarrow x=96\)
Vậy: x=96
d) Ta có: \(\left(5x+3\right)-\left(-24+4\right)=33\)
\(\Leftrightarrow5x+3+24-4-33=0\)
\(\Leftrightarrow5x-10=0\)
\(\Leftrightarrow5x=10\)
\(\Leftrightarrow x=2\)
Vậy: x=2
e) Ta có: \(225-\frac{\left(5x+10\right)}{25}+5=-\left(-20\right)\)
\(\Leftrightarrow225-\frac{5x+10}{25}+5-20=0\)
⇔\(-\frac{5x+10}{25}+210=0\)
\(\Leftrightarrow-\frac{5x+10}{25}=-210\)
⇔\(\frac{5x+10}{25}=210\)
\(\Leftrightarrow5x+10=210\cdot25=5250\)
\(\Leftrightarrow5x=5250-10=5240\)
\(\Leftrightarrow x=1048\)
Vậy: x=1048
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`1,(4x^3+3x^3):x^3+(15x^2+6x):(-3x)=0`
`<=> 4 + 3 + (-5x) + (-2)=0`
`<=> -5x+5=0`
`<=>-5x=-5`
`<=>x=1`
`2,(25x^2-10x):5x +3(x-2)=4`
`<=> 5x - 2 + 3x-6=4`
`<=> 8x -8=4`
`<=> 8x=12`
`<=>x=12/8`
`<=>x=3/2`
`3,(3x+1)^2-(2x+1/2)^2=0`
`<=> [(3x+1)-(2x+1/2)][(3x+1)+(2x+1/2)]=0`
`<=>( 3x+1-2x-1/2)(3x+1+2x+1/2)=0`
`<=>( x+1/2) (5x+3/2)=0`
`@ TH1`
`x+1/2=0`
`<=>x=0-1/2`
`<=>x=-1/2`
` @TH2`
`5x+3/2=0`
`<=> 5x=-3/2`
`<=>x=-3/2 : 5`
`<=>x=-15/2`
`4, x^2+8x+16=0`
`<=>(x+4)^2=0`
`<=>x+4=0`
`<=>x=-4`
`5, 25-10x+x^2=0`
`<=> (5-x)^2=0`
`<=>5-x=0`
`<=>x=5`
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a) -2x - ( x - 17 ) = 34 - ( -x + 25 )
<=> -2x - x + 17 = 34 + x -25
<=> -2x -x - x = 34 - 25 - 17
<=> -4x = -8
<=> x = 2
b) 3x - 32 > -5x + 1
<=> 3x + 5x >1 + 32
<=> 8x > 33
<=> x > \(\dfrac{33}{8}\)
c) 17 + 3 . ( -16x - 37 ) = 2x + 43 - 4x
<=> 17 + ( -48x - 111 ) = -2x + 43
<=> 17 - 48x - 111 = -2x + 43
<=> -48x +2x = 43 - 17 + 111
<=> -46x = 137
<=> x = \(\dfrac{137}{-46}\)
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a) 329 ml – 135 ml = 194 ml | 200 g – 150 g = 50 g |
392 mm + 43 mm = 435 mm |
|
b) 251 ml + 262 ml = 513 ml | 37 g + 63 g – 30 g = 70 g |
87 mm – 17 mm + 10 mm = 80 mm |
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x + 25 = 251
x = 251 - 25
x = 226
Vậy X= 226
AI K MK MK K LẠI
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1. Thực hiện phép tính bằng cách hợp lí :
a) (-46) + (-125) + 46 + 25 = [(-46)+46] + [(-125)+25]
= 0+(-100) = -100
b) 25.(-15) + 25.(-5) + (-20).75 = 25.[(-15)+(-5)] + (-20).75
= 25.(-20) + (-20).75 = (-20).(25+75) = (-20).100 = -2000
c) (-151)+(-37)+(-42)+(-63)+142 =(-151)+[(-37)+(-63)]+[(-42)+142]
= (-151) + [(-100) + 100] = -151
d)32+(-149)+(-311)+(-89)+(-51) = 32+[(-149)+(-51)] + [(-311)+(-89)]
= 32+[(-200)+(-400)] = 32+(-600) = -568
e)-65.(87-17)-87.(17-65) = (-65).87 - (-65).17 - 87.17 + 87.65
= (-65).87 + 65.17 - 87.17 + 87.65 = [(-65).87+87.65] + 65.(17-87)
= 65.(-70) = -4550
g) -43.(53-16) - 53.(16-43) = (-43).53 - (-43).16 - 53.16 + 53.43
= (-43).53 + 43.16 - 53.16 + 53.43 = [(-43).53+53.43] + 16.(43-53)
= 16.(-10) = -160
25 + 5x - 43 = 251
5x - 43 = 251 - 25
5x - 43 = 226
5x = 226 - 43 = 226 - 64
5x = 162
x = 162 : 5 = 32,4
25+5x-43=251
-> 5x - 43 = 251 - 25
-> 5x - 64 = 226
-> 5x = 226 + 64
-> 5x = 290
-> x = 290 : 5
-> x = 58