Viết dưới dạng tích:
a. 49x^2y^4-36z^2t^2
b. 4-12xy^2+9x^2y^4
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a. \(9x^2+30x+25=\left(3x+5\right)^2\)
b. \(\dfrac{4}{9}x^4-16x^2=\left(\dfrac{2}{3}x^2-4x\right)\left(\dfrac{2}{3}x^2+4x\right)=x^2\left(\dfrac{2}{3}x-4\right)\left(\dfrac{2}{3}x+4\right)\)
c. \(a^2y^2+b^2x^2-2axby=\left(ay-bx\right)^2\)
d. \(100-\left(3x-y\right)^2=\left(10-3x+y\right)\left(10+3x-y\right)\)
e. \(\dfrac{12}{5}x^2y^2-9x^4-\dfrac{4}{25}y^4=-\left(9x^4-\dfrac{12}{5}x^2y^2+\dfrac{4}{25}y^4\right)=-\left(3x^2-\dfrac{2}{5}y^2\right)^2\)
f. \(64x^2-\left(8a+b\right)^2=\left(8x-8a-b\right)\left(8x+8a+b\right)\)
g. \(27x^3-a^3b^3=\left(3x-ab\right)\left(9x^2+3xab+a^2b^2\right)\)
1 Viết dưới dạng tich
a)\(49x^2y^4-36z^2t^2\)
\(=\left(7xy^2\right)^2-\left(6zt\right)^2\)
\(=\left(7xy^2-6zt\right)\left(7xy^2+6zt\right)\)
b)\(4-12xy^2+9x^2y^4\)
\(=2^2-2.2.3xy^2+\left(3xy^2\right)^2\)
=\(\left(2-3xy^2\right)^2\)
1/
a) 49x2y4 - 36z2t2 = (7xy2)2 - (6zt)2 = (7xy2 - 6zt)(7xy2 + 6zt)
b) 4 - 12xy2 + 9x2y4 = 22 - 2.2.3xy2 + (3xy2)2 = (2 - 3xy2)2
Đáp án:
a.3x³−5x²+7xa.3x³−5x²+7x
b.−4x²y−10x²y+2xyb.−4x²y−10x²y+2xy
c.−x³+2x²+29x+20c.−x³+2x²+29x+20
d.2x⁴−3x³+2x²+3x−4d.2x⁴−3x³+2x²+3x−4
e.x²−4y²e.x²−4y²
h.2x²−6x+13h.2x²−6x+13
g.3xy⁴−12y²+2x²yg.3xy⁴−12y²+2x²y
f.−2x²y³+y−3f.−2x²y³+y−3
Giải thích các bước giải:
a.3x.(x²−5x+7)a.3x.(x²−5x+7)
=3x³−5x²+7x=3x³−5x²+7x
b.−2xy.(2x³+5x−1)b.−2xy.(2x³+5x−1)
=−4x⁴y−10xy²+2xy=−4x⁴y−10xy²+2xy
c.(x+4).(−x²+6x+5)c.(x+4).(−x²+6x+5)
=−x³+6x²+5x−4x²+24x+20=−x³+6x²+5x−4x²+24x+20
=−x³+2x²+29x+20=−x³+2x²+29x+20
d.(x²−1).(2x²−3x+4)d.(x²−1).(2x²−3x+4)
=2x⁴−3x³+4x²−2x²+3x−4=2x⁴−3x³+4x²−2x²+3x−4
=2x⁴−3x³+2x2+3x−4=2x⁴−3x³+2x2+3x−4
e.(x+2y).(x−2y)e.(x+2y).(x−2y)
=x²−(2y)²=x²−(2y)²
=x²−4y²=x²−4y²
h.(3x−1)²−7(x²+2)h.(3x−1)²−7(x²+2)
=9x²−6x+1−7x²−14=9x²−6x+1−7x²−14
=2x²−6x+13=2x²−6x+13
g.(6x²g.(6x²y⁵−xy³+4x³y²):2xy−xy³+4x³y²):2xy
=3xy⁴−12y²+2x²y=3xy⁴−12y²+2x²y
f.(−12x³y⁴+6xy²−18xy):6xyf.(−12x³y⁴+6xy²−18xy):6xy
=−2x³y³+y−3
a: \(9x^2+30x+25=\left(3x+5\right)^2\)
b: \(\dfrac{4}{9}x^4-16x^2=x^2\left(\dfrac{4}{9}x^2-16\right)=x^2\left(\dfrac{2}{3}x-4\right)\left(\dfrac{2}{3}x+4\right)\)
c: \(\dfrac{12}{5}x^2y^2-9x^4-\dfrac{4}{25}y^4\)
\(=-\left(9x^4-\dfrac{12}{5}x^2y^2+\dfrac{4}{25}y^4\right)\)
\(=-\left(3x^2-\dfrac{2}{5}y^2\right)^2\)
a) \(x^6-4=\left(x^3\right)^2-2^2=\left(x^3-2\right).\left(x^3+2\right)\)
b) \(-9x^2+1=1^2-\left(3x\right)^2=\left(1-3x\right).\left(1+3x\right)\)
c) \(x^{10}-9=\left(x^5\right)^2-3^2=\left(x^5-3\right).\left(x^5+3\right)\)
mk chỉ làm đk bài 1 thui ,thông cảm cho mk nha bạn
\(a;x^6-4=\left(x^3\right)^2-2^2=\left(x^3-2\right)\left(x^3+2\right)\)
\(b;-9x^2+1=1^2-3x^2=\left(1-3x\right).\left(1+3x\right)\)
\(c;x^{10}-9=\left(x^5\right)^2-3^2=\left(x^5-3\right).\left(x^5+3\right)\)
\(#LTH\)
Trả lời:
\(9x^2+2y^2-6xy-4y+4\)
\(=\left(9x^2-6xy+y^2\right)+\left(y^2-4y+4\right)\)
\(=\left(3x-y\right)^2+\left(y-2\right)^2\)
A, \(\frac{9}{4}x^2+3x+4\)
= \(\left(\frac{3}{2}x^2\right)+2\cdot\frac{3}{2}x\cdot2+2^2\)
= \(\left(\frac{3}{2}x+2\right)^2\)
a) \(49x^2y^4-36z^2t^2\)
\(=\left(7xy^2\right)^2-\left(6zt\right)^2\)
\(=\left(7xy^2-6zt\right).\left(7xy^2+6zt\right).\)
b) \(4-12xy^2+9x^2y^4\)
\(=2^2-2.2.3xy^2+\left(3xy^2\right)^2\)
\(=\left(2-3xy^2\right)^2.\)
Chúc bạn học tốt!