Phân tích đa thức thành nhân tử
3abc*(3b - c) - 3ac*(3c - a) - 3ab*(3a + b) + 28abc
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A=9b^2c-3bc^2-9ac^2-3a^2c-9a^2b-3a^2+28abc
A=9.(b^2c-ac^2-a^2.b)-3.(bc^2+a^2.c+3a^2)+28abc
A=9.(b.(bc-a^2)-ac^2)-3.(c.(bc+a^2)+3a^2)+28abc
k dung mik nhe!!!!!
\(a^3-b^3+c^3+3abc\)
\(=\left(a-b\right)^3+c^3+3abc+3a^2b-3ab^2\)
\(=\left[\left(a-b\right)^3+c^3\right]+3ab\left(c+a-b\right)\)
\(=\left(c+a-b\right)\left[\left(a-b\right)^2-\left(a-b\right)c+c^2\right]+3ab\left(c+a-b\right)\)
\(=\left(c+a-b\right)\left(a^2-2ab+b^2-ac+bc+c^2+3ab\right)\)
\(=\left(c+a-b\right)\left(a^2+b^2+c^2+ab-ac+bc\right)\)
a) 4x2 - 1
= (2x - 1)(2x + 1)
b) ax + 3a - bx - 3b
= a(x + 3) - b(x + 3)
= (x + 3)(a - b)
c) 4x2 - 8xy + 4y2 - 16
= (2x - 2y)2 - 42
= (2x - 2y - 4)(2x - 2y + 4)
d) 2x2 - 3x - 9
= 2x2 + 3x - 6x - 9
= x(2x + 3) - 3(2x + 3)
= (2x + 3)(x - 3)
a) x2+x-2
= x2-x+2x-2
= x(x-1)+2(x-1)
= (x+2)(x-1)
b) 2x2+5x+3
= 2x2+2x+3x+3
= 2x(x+1)+3(x+1)
= (2x+3)(x+1)
c) 3x2+5x-2
= 3x2+6x-1x-2
= 3x(x+2)-1(x+2)
= (3x-1)(x+2)
\(abc-\left(ab+bc+ac\right)+\left(a+b+c\right)-1=\left(abc-ab\right)-\left(bc-b\right)-\left(ac-a\right)+\left(c-1\right)=ab\left(c-1\right)-b\left(c-1\right)-a\left(c-1\right)+\left(c-1\right)=\left(c-1\right)\left(ab-b-a+1\right)=\left(c-1\right)\left[b\left(a-1\right)-\left(a-1\right)\right]=\left(a-1\right)\left(b-1\right)\left(c-1\right)\)
\(=4ab\left(ab+ax+bx+x^2\right)=4a^2b^2+4a^2bx+4ab^2x+4abx^2\)
\(\left(ab-1\right)^2+\left(a+b\right)^2=a^2b^2-2ab+1+a^2+2ab+b^2=a^2+b^2+a^2b^2+1=a^2\left(b^2+1\right)+\left(b^2+1\right)=\left(a^2+1\right)\left(b^2+1\right)\)