2.4+4.6+....+48.50+50.52
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
6A=2.4.6+4.6.(8-2)+.........+50.52.(54-48)
6A=2.4.6+4.6.8-2.4.6+............+50.52.54-48.50.52
6A=50.52.54
A=50.52.54:6
A=23400
\(\dfrac{2}{2.4}+\dfrac{2}{4.6}+................+\dfrac{2}{50.52}\)
\(=\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+..............+\dfrac{1}{50}-\dfrac{1}{52}\)
\(=\dfrac{1}{2}-\dfrac{1}{52}=\dfrac{25}{52}\)
\(\dfrac{2}{2.4}+\dfrac{2}{4.6}+.....+\dfrac{2}{50.52}\)
\(=\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+.....+\dfrac{1}{50}-\dfrac{1}{52}\)
\(=\dfrac{1}{2}-\dfrac{1}{52}=\dfrac{25}{52}\)
\(=\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{6}+...+\dfrac{1}{50}-\dfrac{1}{52}=\dfrac{1}{2}-\dfrac{1}{52}=\dfrac{25}{52}\)
Ta có: \(A=\frac{1}{2\cdot4}+\frac{1}{4\cdot6}+...+\frac{1}{48\cdot50}\)
\(\Rightarrow2\cdot A=\frac{2}{2\cdot4}+\frac{2}{4\cdot6}+...+\frac{2}{48\cdot50}\)
\(\Rightarrow2\cdot A=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+...+\frac{1}{48}-\frac{1}{50}\)
\(\Rightarrow2\cdot A=\frac{1}{2}-\frac{1}{50}=\frac{12}{25}\)
\(\Rightarrow2\cdot A=\frac{12}{25}\)
hay \(A=\frac{12}{25}:2=\frac{12}{25}\cdot\frac{1}{2}=\frac{12}{50}=\frac{6}{25}\)
gọi tổng của 1+2+3+4+...+79 là M
2+3+4+...+80 là N
ta có A = M.N
từ 1 đến 79 hay từ 2 đến 80 có (79-1) chia 1 + 1=79
M = (79+1).79 chia 2= 3160
N = (80+2).79chia 2= 3239
A = 3160 .3239 = 10235240
Đặt \(A=2.4+4.6+...+50.52\)
\(\Rightarrow6A=2.4.6+4.6.6+...+50.52.6\)
\(=2.4.6+4.6.\left(8-2\right)+....+50.52.\left(54-48\right)\)
\(=2.4.5+4.6.8-2.4.6+...+50.52.54-48.50.52\)
\(=50.52.54\)
\(\Rightarrow A=\frac{50.52.54}{6}=23400\)
\(\text{Đặt A = 2.4 + 4.6 + ... + 50.52}\)
\(\text{⇒6A = 2.4.6 + 4.6.6 + ... + 50.52.6}\)
\(\text{6A= 2.4.6 + 4.6. 8 − 2 + .... + 50.52. 54 − 48 }\)
\(\text{6A= 2.4.5 + 4.6.8 − 2.4.6 + ... + 50.52.54 − 48.50.52}\)
\(\text{6A=50.52.54 }\)
\(\Rightarrow A=\)\(\frac{\text{50.52.54 }}{6}\)\(=23400\)