6,25 - x = 3phan 5+1phan6
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a.|x+3/4|-1/3=0
=>|x-3/4|=1/3
=>x-3/4=1/3 hoặc x-3/4=-1/3
=>x=1/3+3/4 hoặc x =-1/3+3/4
=>x=... x =...
b. 3-|2x+5|=10
=> |2x+5| = 3-10
=> |2x+5| = -7 ( vô lí vì |x| \(\ge\)0)
=> không tồn tại x.
c. 12+3.|7x-4|=4
=> 3.|7x-4|=4-12
=> 3.|7x-4|=-8
=> |7x-4|=-8/3(vô lí tương tự)
=> không tồn tại x
\(\frac{x+3}{-4}=\frac{-9}{x+3}\Rightarrow\left(x+3\right)^2=\left(-4\right).\left(-9\right)\)
\(\Rightarrow\left(x+3\right)^2=36\)
\(\Rightarrow\left(x+3\right)^2=6^2\) hoặc \(\left(x+3\right)^2=\left(-6\right)^2\)
\(\Rightarrow x+3=6\) hoặc \(x+3=-6\)
\(\Rightarrow x=3\) hoặc \(x=-9\)
5.x = 6,25
x = 6,25 : 5
x = 1,25
và 5 + x = 6,25
x = 6,25 – 5
x = 1,25
\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{11.12}\)
\(=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\)
\(=\frac{1}{1}-\frac{1}{12}\)
\(=\frac{11}{12}\)
\(A=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\)
\(A=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+\frac{1}{4x5}+...+\frac{1}{11x12}\)
\(A=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+\frac{5-4}{4x5}+...+\frac{12-11}{11x12}\)
\(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}\)
\(A=1-\frac{1}{12}=\frac{11}{12}\)
0,5 . 11/3 . 75% + 3/5
= 11/8 + 3/5
= 79/40
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\(\dfrac{3}{4}-\left(\dfrac{5}{6}\right)^2\)
\(=\dfrac{3}{4}-\dfrac{25}{36}\)
\(=\dfrac{27-25}{36}=\dfrac{2}{36}=\dfrac{1}{18}\)
3/4-(5/6)^2=3/4-25/36=27/36-25/36=2/36=1/18
Dễ mà mấy em nhớ like cho chị nhé(Quách Tố Như)
\(6,25-x=\dfrac{3}{5}+\dfrac{1}{6}\\ 6,25-x=\dfrac{23}{30}\\ x=6,25-\dfrac{23}{30}\\ x=\dfrac{329}{60}\)