tính nhanh bt a=1/3-1/3^2+1/3^3-1/3^4+....+1/3^99-1/3^100
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Ta có \(63,1.2-21,3.6=0,9.7.10.1,2-21.3,6\)
\(=6,3.1,2-21.3,6\)
\(=0,9.7.4.3-7.3.0,9.4\)
\(=6,3.1,2-6,3.1,2\)
\(=0\)
\(\Rightarrow\dfrac{\left(1+2+......+100\right).\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{9}\right)\left(63.1,2-21.3,6\right)}{1-2+3-4+.....+99-100}=\dfrac{\left(1+2+.....+100\right)\left(\dfrac{1}{2}-\dfrac{1}{3}-\dfrac{1}{7}-\dfrac{1}{9}\right)0}{1-2+3-4+......+99-100}=0\)
Ta có:
\(A=\frac{1}{3}-\frac{1}{3^2}+\frac{1}{3^3}-\frac{1}{3^4}+...+\frac{1}{3^{99}}-\frac{1}{3^{100}}\)
=> \(3A=1-\frac{1}{3}+\frac{1}{3^2}-\frac{1}{3^3}+...+\frac{1}{3^{98}}-\frac{1}{3^{99}}\)
=> \(A+3A=1-\frac{1}{3^{100}}\)
=> \(4A=\frac{3^{100}-1}{3^{100}}\)
=> \(A=\frac{3^{100}-1}{4.3^{100}}\)
\(S=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+....+\frac{1}{99.100}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{99}-\frac{1}{100}\)
\(=1-\frac{1}{100}=\frac{99}{100}\)
3A=3.(1/3-1/3^2+1/3^3-...+1/3^99-1/3^100)
3A+A=(1-1/3+1/3^2+1/3^3-...+1/3^98-1/3^99)+(1/3-1/3^2+1/3^3-...+1/3^99-1/3^100)
4A= 1-1/3+1/3^2+1/3^3-...+1/3^98-1/3^99+1/3-1/3^2+1/3^3-...+1/3^99-1/3^100
4A=1-1/3^100
A=(1-1/3^100):4
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