Question

[Nguyễn Duy]

3,Tính hợp lý

a,\(\frac{3}{7}\cdot\frac{4}{9}+\frac{3}{7}\cdot\frac{5}{9}+\frac{5}{14}\)

b,\(\frac{-11}{23}\cdot\frac{6}{7}+\frac{8}{9}\cdot\frac{-11}{23}-\frac{1}{23}\)

Giúp mình nhé!!!

Answer 1

[phunganhtuyet]

a,\(\frac{3}{7}.\frac{4}{9}+\frac{3}{7}.\frac{5}{9}+\frac{5}{14}\)

\(=\frac{3}{7}.\left(\frac{4}{9}+\frac{5}{9}\right)+\frac{5}{14}\)

\(=\frac{3}{7}.1+\frac{5}{14}\)

\(=\frac{3}{7}+\frac{5}{14}=\frac{6}{14}+\frac{5}{14}=\frac{11}{14}\)

b,\(\frac{-11}{23}.\frac{6}{7}+\frac{8}{9}.\frac{-11}{23}-\frac{1}{23}\)

\(=\)\(\frac{-11}{23}.\left(\frac{6}{7}+\frac{8}{9}\right)-\frac{1}{23}\)

\(=\frac{-11}{23}.\frac{110}{63}-\frac{1}{23}\)

=\(\frac{-1210}{1449}\)-\(\frac{1}{23}\)

\(=\frac{-1273}{1449}\)