\(25\%-2\frac{1}{3}+0,5.\frac{12}{5}\)
K
Khách
Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
Những câu hỏi liên quan
3 tháng 5 2019
\(\frac{5}{7}\times\frac{1}{3}-\frac{5}{7}\times\frac{1}{4}-\frac{5}{7}\times\frac{1}{2}\)
\(=\frac{5}{7}\times\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right)\)
\(=\frac{5}{7}\times\left(\frac{4}{12}-\frac{3}{12}-\frac{6}{12}\right)\)
\(=\frac{5}{7}\times\left(\frac{4-3-6}{12}\right)\)
\(=\frac{5}{7}\times\frac{-5}{12}\)
\(=\frac{5\times\left(-5\right)}{7\times12}\)
\(=\frac{-25}{84}\)
3 tháng 5 2019
\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)
= \(\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right).1\)
\(=\frac{5}{7}.\frac{-5}{12}\)
\(=-\frac{25}{84}\)
10 tháng 5 2016
\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)
\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)
\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)
\(=\frac{5}{7}.0=0\)
10 tháng 5 2016
c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)
\(=\frac{27}{5}.10=27.2=54\)
\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)
\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)
LV
3 tháng 8 2016
25% - 1 1/2 + 0,5 . 12/5
= 1/4 - 3/2 + 1/2 . 12 /5
= 1/4 - 3/2 + 6/5
= -5/4 + 6/5
= -1/20
3 tháng 8 2016
25% - 1 1/2 + 0.5 x 12/5
= 0.25 - 1.5 + 0.5 x 2.4
= 0.25 - 1.5 + 1.2
= 0.25 - 2.7
= -2.45
22 tháng 7 2021
a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}\)
\(=\frac{2}{3}-\frac{2}{5}=\frac{4}{15}\)
b) \(\frac{-2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}\)
\(=\frac{5}{8}\left(-\frac{2}{5}+\frac{3}{5}\right)\)
\(=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)
c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}\)
\(=0,25-1,5+0,5\cdot2,4\)
\(=0,25-1,5+1,2=-0,05\)
LH
22 tháng 7 2021
a) \(\frac{2}{3}-\frac{5}{7}\cdot\frac{14}{25}=\frac{2}{3}-\frac{2}{5}=\frac{10-6}{15}=\frac{4}{15}\)
b) \(-\frac{2}{5}\cdot\frac{5}{8}+\frac{5}{8}\cdot\frac{3}{5}=\frac{5}{8}\cdot\left(-\frac{2}{5}+\frac{3}{5}\right)=\frac{5}{8}\cdot\frac{1}{5}=\frac{1}{8}\)
c) \(25\%-1\frac{1}{2}+0,5\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{1}{2}\cdot\frac{12}{5}=\frac{1}{4}-\frac{3}{2}+\frac{6}{5}=\frac{5-30+24}{20}=-\frac{1}{20}\)
~~ Chúc bạn học tốt ~~
2 tháng 9 2017
Phan Hoàng Mai
Tính :
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right).\frac{3}{8}-72:12^2\)
\(=\left(-\frac{5}{10}-\frac{3}{5}\right):\frac{-22}{25}+\left(\frac{2}{25}-\frac{108}{100}\right).\frac{3}{8}-72:144\)
\(=\left(-\frac{5}{10}-\frac{6}{10}\right).\frac{-25}{22}+\left(\frac{8}{100}-\frac{108}{100}\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{-11}{10}.\frac{-25}{22}+\left(-1\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{\left(-11\right).\left(-25\right)}{10.22}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{5}{4}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{10}{8}+\frac{-3}{8}-\frac{4}{8}\)
\(=\frac{3}{8}\)
Chúc bạn học tốt!!!
2 tháng 9 2017
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\cdot\frac{3}{8}-72:12^2\)
=\(\left(-\frac{1}{2}-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-\frac{27}{25}\right)\cdot\frac{3}{8}-\frac{72}{144}\)
=\(\left(-\frac{11}{10}.\left(-\frac{25}{22}\right)\right)-1\cdot\frac{3}{8}-\frac{1}{2}\)
= \(\frac{5}{4}-\frac{3}{8}-\frac{1}{2}\)
= \(\frac{10}{8}-\frac{3}{8}-\frac{4}{8}=\frac{3}{8}\)
2 tháng 9 2017
\(\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2\)
\(=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}\)
\(=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}\)
\(=\dfrac{3}{8}\)
11 tháng 12 2019
a) \(\frac{15}{12}+\frac{5}{13}-\frac{3}{12}-\frac{18}{13}=\left(\frac{15}{12}-\frac{3}{12}\right)+\left(\frac{5}{13}-\frac{18}{13}\right)\)
\(=1+\left(-1\right)\)
\(=0\)
b) \(\frac{11}{24}-\frac{5}{41}+\frac{13}{24}+0,5-\frac{36}{41}=\left(\frac{11}{24}+\frac{13}{24}\right)+\left(-\frac{5}{41}-\frac{36}{41}\right)+0,5\)
\(=1+\left(-1\right)+0,5\)
\(=0,5\)
_Học tốt nha_
11 tháng 12 2019
a, \(\frac{15}{12}\)+ \(\frac{5}{13}\)- \(\frac{3}{12}\)-\(\frac{18}{13}\)
= \(\frac{5}{4}\)+ \(\frac{5}{13}\) - \(\frac{1}{4}\) - \(\frac{18}{13}\)
= \(\left(\frac{5}{4}-\frac{1}{4}\right)\)+ \(\left(\frac{5}{13}-\frac{18}{13}\right)\)
= 1 - 1 = 0
b, \(\frac{11}{24}\)- \(\frac{5}{41}\)+ \(\frac{13}{24}\)+ 0,5 - \(\frac{36}{41}\)
= \(\left(\frac{11}{24}+\frac{13}{24}\right)\)- \(\left(\frac{5}{41}+\frac{36}{41}\right)\)+ 0,5
= 1 - 1 + 0,5 = 0,5
c, \(\left(-\frac{3}{4}+\frac{2}{3}\right):\frac{5}{11}+\left(-\frac{1}{4}+\frac{1}{3}\right):\frac{5}{11}\)
=\(\left(-\frac{3}{4}+\frac{2}{3}\right).\frac{11}{5}+\left(-\frac{1}{4}+\frac{1}{3}\right).\frac{5}{11}\)
= \(\frac{11}{5}.\left(-\frac{3}{4}+\frac{2}{3}-\frac{1}{4}+\frac{1}{3}\right)\)
= \(\frac{11}{5}.\left[\left(-\frac{3}{4}-\frac{1}{4}\right)+\left(\frac{2}{3}+\frac{1}{3}\right)\right]\)
= \(\frac{11}{5}.\left[\left(-1\right)+1\right]\)
= 0
d, \(\left(-3\right)^2.\left(\frac{3}{4}-0,25\right)-\left(3\frac{1}{2}-1\frac{1}{2}\right)\)
= \(9.\left(0,75-0,25\right)-2\)
= 9. 0,5 - 2 = 2,5
e, \(\frac{13}{25}+\frac{6}{41}-\frac{38}{25}+\frac{35}{41}-\frac{1}{2}\)
= \(\left(\frac{13}{25}-\frac{38}{25}\right)+\left(\frac{6}{41}+\frac{35}{41}\right)-\frac{1}{2}\)
= -1 + 1 - \(\frac{1}{2}\)
= \(-\frac{1}{2}\)
\(25\%-2\frac{1}{3}+0,5.\frac{12}{5}\)
\(=\frac{1}{4}-\frac{7}{3}+\frac{1}{2}.\frac{12}{5}\)
\(=\frac{1}{4}-\frac{7}{3}+\frac{6}{5}\)
\(=\frac{1}{4}+\frac{-7}{3}+\frac{6}{5}\)
\(=\frac{15}{60}+\frac{-140}{60}+\frac{72}{60}\)
\(=\frac{-53}{60}\)