A=3/11.4/13+(3/13.4/11-1/13)
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17 tháng 8 2023
1:
a: =23/27-11/17+4/27+28/17
=23/27+4/27+28/17-11/17
=1+1=2
b: \(=\dfrac{2}{3}\cdot\left(\dfrac{7}{9}+\dfrac{2}{9}\right)-\dfrac{2}{9}\)
=2/3-2/9
=6/9-2/9
=4/9
c: \(=\dfrac{11}{5}\cdot\dfrac{7}{3}-\dfrac{1}{3}\cdot\dfrac{11}{5}\)
=11/5(7/3-1/3)
=11/5*2
=22/5
d: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{2024}{2023}=\dfrac{2024}{2}=1012\)
e: \(=\dfrac{1}{2}\cdot\dfrac{2}{3}\cdot...\cdot\dfrac{2022}{2023}=\dfrac{1}{2023}\)
HH
1
3 tháng 3 2021
Ta có: \(\dfrac{8.5-8.2}{16}=\dfrac{8\left(5-2\right)}{16}=\dfrac{8.3}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{11.3}{-11}=-3\)
15 tháng 5 2020
\(A=\frac{2}{13}.\frac{5}{9}+\frac{2}{13}.\frac{4}{9}+\frac{11}{13}=\frac{2}{13}.\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{3}\)
\(=\frac{2}{13}.1+\frac{11}{13}\)
\(=\frac{2}{13}+\frac{11}{13}=1\)
HN
15 tháng 5 2020
\(A=\frac{2}{13}\cdot\frac{5}{9}+\frac{2}{13}\cdot\frac{4}{9}+\frac{11}{13}\)
\(A=\frac{2}{13}\left(\frac{5}{9}+\frac{4}{9}\right)+\frac{11}{13}\)
\(A=\frac{2}{13}\cdot1+\frac{11}{13}\)
\(A=\frac{2}{13}+\frac{11}{13}\)
\(A=\frac{13}{13}=1\)
VN
28 tháng 1 2023
\(\dfrac{-63}{72}=\dfrac{-7}{8}\)
\(\dfrac{20}{-140}=\dfrac{-1}{7}\)
\(\dfrac{3.10}{5.24}=\dfrac{30}{120}=\dfrac{1}{4}\)
\(\dfrac{3.7.11}{22.9}=\dfrac{231}{198}=\dfrac{7}{6}\)
\(\dfrac{8.5-8.2}{16}=\dfrac{24}{16}=\dfrac{3}{2}\)
\(\dfrac{11.4-11}{2-13}=\dfrac{33}{-11}=-3\)
H9
HT.Phong (9A5)
CTVHS
26 tháng 6 2023
a. \(\dfrac{8,5-8,2}{16}=\dfrac{0,3}{16}=\dfrac{3}{160}\)
b. \(\dfrac{2\cdot14}{7\cdot8}=\dfrac{1\cdot2}{1\cdot4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c. \(\dfrac{11\cdot4-11}{2-13}=\dfrac{11\left(4-1\right)}{-11}=\dfrac{1\cdot3}{-1}=-3\)
d. \(\dfrac{49+7\cdot49}{49}=\dfrac{49\cdot\left(1+7\right)}{49}=\dfrac{8}{1}=8\)
CP
1
