hộ toyyy vs...
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hộ toyyy vs ah
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DT
Đỗ Thanh Hải
CTVVIP
20 tháng 5 2021
1 Your sister is interested in doing DIY in her free time, isn't she?
2 Unless that girl study harder, she will fail the exam
3 My father has given up smoking since last year
4 Mary wanted to know what Peter would give his brother on his birthday the day after
20 tháng 5 2021
1. Your sister is interested in doing DIY in her free time, isn't she?
2. Unless that girl studies harder, she'll fail the exam.
3. My father has given up smoking since last year.
4. Mary wanted to know what Peter would give his brother on his birthday the next day.
DT
Đỗ Thanh Hải
CTVVIP
6 tháng 6 2021
III
1 appreciated
2 worried
3 tense
4 confident
5 delighted
6 frustrated
7 calm
8 relaxed
9 self-disciplined
10 depressed
V
1 had resolved
2 has taken
3 Did you say
4 not to take
5 wanted
6 is being repaired
7 taking
8 to think
9 had worked
10 was washing - dropped
11 will find
12 faces
13 turned
14 to give
15 will empathise
3 tháng 9 2021
Đặt \(A=\dfrac{1}{\sqrt[3]{a+7b}}+\dfrac{1}{\sqrt[3]{b+7c}}+\dfrac{1}{\sqrt[3]{c+7a}}\)
\(A=\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(a+7b\right)}}+\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(b+7c\right)}}+\dfrac{\sqrt[3]{64}}{\sqrt[3]{8.8\left(c+7a\right)}}\)
\(\ge\dfrac{4}{\dfrac{8+8+a+7b}{3}}+\dfrac{4}{\dfrac{8+8+b+7c}{3}}+\dfrac{4}{\dfrac{8+8+c+7a}{3}}\ge\dfrac{\left(2+2+2\right)^2}{\dfrac{8+8+a+7b+8+8+b+7c+8+8+c+7a}{3}}\)
\(=\dfrac{36.3}{8\left(a+b+c\right)+48}=\dfrac{3}{2}\)
Vậy \(A_{min}=\dfrac{3}{2}\Leftrightarrow a=b=c=1\)
DT
0
sossssss
3 tháng 9 2021
Xét ΔABC vuông tại A có
\(BC^2=AB^2+AC^2\)
hay AC=12(cm)
Xét ΔACB vuông tại A có AH là đường cao ứng với cạnh huyền BC
nên \(\left\{{}\begin{matrix}AC^2=CH\cdot BC\\AH\cdot BC=AB\cdot AC\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}CH=\dfrac{144}{13}\left(cm\right)\\AH=\dfrac{60}{13}\left(cm\right)\end{matrix}\right.\)
20 tháng 9 2015
Hình vẽ : tự vẽ nha
Sabc = \(\frac{1}{2}AH.BC=\frac{1}{2}BK.AC\)
=> \(AH.BC=AC.BK\)
=> \(\frac{AH}{BK}=\frac{AC}{BC}=\frac{15.6}{12}=\frac{13}{10}\)
=> \(\frac{AC}{13}=\frac{BC}{10}=t\)
=> \(AC=13t;BC=10t\)
Tam giác ABC cân có AH là đg cao => AH là t tuyến => BH = HC = 1/2 BC = 1/2.10t = 5t
TAm giác AHC vuông tại H , theo py ta go :
\(AC^2-HC^2=15.6^2\)
=> \(169t^2-25t^2=15.6^2\)
tính ra t thay vào tìm ra BC
20 tháng 9 2015
2SABC = AH.BC = AC.BK
ð 15,6BC = 12AC
ð BC = 12/15,6AC
ð CH = 6/15,6AC
ð AH2 = AC2 – HC2 = 144/169AC2
ð AH = 12/13 AC
ð 15,6 = 12/13AC
ð AC = 16,9
ð BC = 12/15,6 AC = 13
Tom was born on October 24th nhé.