21X-5x2+3-7=7xX
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21x - 5.2 + 3 - 7 = 7x
=> 21x - 10 - 4 = 7x
=> 2x - 14 = 7x
=> 2x - 7x = 14
=> -5x = 14
=> x = -14/5
Vậy...
a: \(81x^5-x^3\)
\(=x^3\left(81x^2-1\right)\)
\(=x^3\left(9x-1\right)\left(9x+1\right)\)
b: \(9x^2y-12xy+4y\)
\(=y\left(9x^2-12x+4\right)\)
\(=y\left(3x-2\right)^2\)
c: \(\left(5-x\right)^2-16\left(x-2\right)^2\)
\(=\left(x-5\right)^2-\left(4x-8\right)^2\)
\(=\left(x-5-4x+8\right)\left(x-5+4x-8\right)\)
\(=-3\left(x-1\right)\left(5x-13\right)\)
d: Ta có: \(9x^2-y^2-21x-7y\)
\(=\left(3x-y\right)\left(3x+y\right)-7\left(3x+y\right)\)
\(=\left(3x+y\right)\left(3x-y-7\right)\)
e: Ta có: \(-y^2+8y-16+9x^2\)
\(=-\left(y^2-8y+16-9x^2\right)\)
\(=-\left(y-4-3x\right)\left(y-4+3x\right)\)
f: Ta có: \(5x^2-4x-1\)
\(=5x^2-5x+x-1\)
\(=5x\left(x-1\right)+\left(x-1\right)\)
\(=\left(x-1\right)\left(5x+1\right)\)
3/7xX-15=3và3/7
\(\dfrac{3}{7}xX-15=\dfrac{24}{7}\)
\(\dfrac{3}{7}xX=\dfrac{24}{7}+15\)
\(\dfrac{3}{7}xX=\dfrac{129}{7}\)
\(X=\dfrac{129}{7}:\dfrac{3}{7}\)
\(X=43\)
Hình như Lê có khó khăn khi viết dấu `xx` trong phép tính đúng hem :v
Câu 2:
\(=\dfrac{x^2\left(2x-5\right)+3\left(2x-5\right)}{2x-5}=x^2+3\)
Câu 3:
\(\Leftrightarrow2n^2-4n+5n-10+3⋮n-2\)
\(\Leftrightarrow n-2\in\left\{1;-1;3;-3\right\}\)
hay \(n\in\left\{3;1;5;-1\right\}\)
a,Ta có:\(\frac{12}{7}.x=\frac{15}{6}\)
\(x=\frac{15}{6}:\frac{12}{7}\)
\(x=\frac{15}{6}.\frac{7}{12}=\frac{35}{24}\)
b,\(x=\frac{29}{7}-\frac{3}{2}=\frac{58-21}{14}=\frac{37}{14}\)
a: \(x^2-y^2-x-y\)
\(=\left(x-y\right)\left(x+y\right)-\left(x+y\right)\)
\(=\left(x+y\right)\left(x-y-1\right)\)
f: \(x^3-5x^2-5x+1\)
\(=\left(x+1\right)\left(x^2-x+1\right)-5x\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-6x+1\right)\)
a: \(5x^2\left(3x^3-2x^2+x+2\right)\)
\(=15x^5-10x^4+5x^3+10x^2\)
b: \(3x^4\left(-2x^3+5x^2-\dfrac{2}{3}x+\dfrac{1}{3}\right)\)
\(=-6x^7+15x^6-2x^5+x^4\)
13/5 x 2/3 + 7/3 x 2/3 = (13/5 + 7/3) x 2/3 = 74/15 x 2/3=28/5
21x - 5.2 + 3 - 7 = 7x
=> 21x - 10 - 4 = 7x
=> 21x - 14 = 7x
=> 21x - 7x = 14
=> 14x = 14
=> x = 14 : 14
=> x = 1
Kết quả
= > x = 1
Hok tốt