x phần 15 bằng âm 4 phần 5 cách giải
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\(\frac{1}{5x}+\frac{4}{5x}=-10\Rightarrow\frac{1+4}{5x}=-10\)
\(\frac{5}{5x}=10\Rightarrow\frac{1}{x}=10\Rightarrow x=\frac{1}{10}\)
Thế này à :
\(\frac{1}{5}x+\frac{4}{5}x=-10\)
\(x\left(\frac{1}{5}+\frac{4}{5}\right)=-10\)
\(x.1=-10\)
\(=>x=-10:1=-10\)
\(\dfrac{\left(-2\right).2}{15.2}-\dfrac{3.3}{10.3}=\dfrac{-4}{30}-\dfrac{9}{30}=\dfrac{-13}{30}\)
\(=\dfrac{-2}{15}+\dfrac{3}{10}=\dfrac{-4}{30}+\dfrac{9}{30}=\dfrac{5}{30}=\dfrac{1}{6}\)
\(=\dfrac{1}{10}+\dfrac{1}{12}+\dfrac{1}{15}=\dfrac{6}{60}+\dfrac{5}{60}+\dfrac{4}{60}=\dfrac{15}{60}=\dfrac{1}{4}\)
\(=\dfrac{1.6}{10.6}-\dfrac{\left(-1\right).5}{12.5}+\dfrac{1.4}{15.4}=\dfrac{6}{60}+\dfrac{-5}{60}+\dfrac{4}{60}=\dfrac{5}{60}=\dfrac{1}{12}\)
\(a.32,5-3\cdot0,87=32,5-2,61=29,89\)
\(8,5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8,5\cdot\left(\dfrac{3}{2}+\dfrac{4}{4}\right):5\\ =8,5\cdot\left(\dfrac{6}{4}+\dfrac{4}{4}\right):5\\ =8,5\cdot\dfrac{10}{4}:5\\ =\dfrac{85}{4}:5\\ =\dfrac{17}{4}\)
\(b.30,96-6,45+14,4:3=30,96-6,45+4,8\\ =29,31\)
\(\dfrac{2}{5}\cdot\left(\dfrac{4}{5}-\dfrac{1}{2}\right)=\dfrac{2}{5}\cdot\left(\dfrac{8}{10}-\dfrac{5}{10}\right)\\ =\dfrac{2}{5}\cdot\dfrac{3}{10}=\dfrac{3}{25}\)
bài 2
\(a.2,5\cdot12,5\cdot8\cdot0,4=\left(2,5\cdot0,4\right)\left(12,5\cdot8\right)\\ =1\cdot100=100\)
b,\(\dfrac{12}{15}\cdot\dfrac{5}{6}\cdot\dfrac{3}{20}\cdot\dfrac{32}{5}=\dfrac{12\cdot5\cdot3\cdot32}{15\cdot6\cdot20\cdot5}\\ =\dfrac{3\cdot4\cdot5\cdot3\cdot4\cdot8}{3\cdot5\cdot2\cdot3\cdot5\cdot4\cdot5}=\dfrac{16}{25}\)
Bài 1:
a) \(32.5-3\cdot0.87=32.5-2.61=29.89\)
\(8.5\cdot\left(1\dfrac{1}{2}+\dfrac{4}{4}\right):5=8.5\cdot\dfrac{5}{2}:5=\dfrac{17}{2}\cdot\dfrac{5}{2}:5=\dfrac{85}{4}\cdot\dfrac{1}{5}=\dfrac{17}{4}\)
2/x-2/15=-8/15 2/x= -8/15+2/15 => 2/x=-6/15=>2/x=2/-5=>x=-5 Vậy x=-5
\(\left|\frac{x}{-4}\right|=\left|\frac{-5}{20}\right|\)
P/S : Hông chắc :>
lấy âm bốn phần năm nhân mười lăm :))))
x15 = -4/5
x/15 = -12/15 Hok tốt
x = -12