23 : 7 - 5 =
=
K
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27 tháng 5 2020
-30/117+-35/207+35/207
-30/117+0
-30/117
mn h cho mik nha
20 tháng 2 2023
Ai rảnh mà làm hộ mày, ngu như con chó mới không biết làm
NT
2
21 tháng 11 2018
\(5.\frac{5}{7}+\frac{7}{23}+0,5.\frac{5}{7}+\frac{16}{23}+\frac{1}{2}\)
\(=5.\frac{5}{7}+0,5.\frac{5}{7}+\frac{7}{23}+\frac{16}{23}+\frac{1}{2}\)
\(=(5+0,5).\frac{5}{7}+\frac{1}{23}.\left(7+16\right)+\frac{1}{2}\)
\(=\frac{11}{2}.\frac{5}{7}+\frac{1}{23}.23+\frac{1}{2}\)
\(=\frac{55}{14}+\frac{23}{23}+\frac{1}{2}\)
\(=\frac{55}{14}+\frac{1}{2}+1\)
\(=\frac{31}{7}+1=\frac{38}{7}\)
21 tháng 11 2018
\(5\cdot\frac{5}{7}+\frac{7}{23}+0.5\cdot\frac{5}{7}+\frac{16}{23}\)
=\(\left(5+0.5\right)\cdot\frac{5}{7}+\left(\frac{7}{23}+\frac{16}{23}\right)\)
=5.5*\(\frac{5}{7}+1\)
=\(\frac{69}{14}\)
16 tháng 2 2021
Ta có: \(23\dfrac{1}{4}:\left(-\dfrac{3}{7}\right)-23\dfrac{1}{4}:\left(-\dfrac{5}{7}\right)\)
\(=\dfrac{93}{4}\cdot\dfrac{-7}{3}-\dfrac{93}{4}\cdot\dfrac{-7}{5}\)
\(=\dfrac{93}{4}\cdot\left(-\dfrac{7}{3}+\dfrac{7}{5}\right)\)
\(=\dfrac{93}{4}\cdot\dfrac{-14}{15}=-\dfrac{217}{10}\)
LC
12 tháng 8 2015
7/23.5/29+7/29.18/23-7/29
=(7.5)/(23.29)+7/29.18/23-7/29
=7/29.5/23+7/29.18/23-7/29.1
=7/29.(5/23+18/23-1)
=7/29.(1-1)
=7/29.0
=0
12 tháng 8 2015
\(\frac{7}{23}\cdot\frac{5}{29}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\frac{5}{23}+\frac{7}{29}\cdot\frac{18}{23}-\frac{7}{29}\)
\(=\frac{7}{29}\cdot\left(\frac{5}{23}+\frac{18}{23}-1\right)\)
\(=\frac{7}{29}\cdot0\)
\(=0\)
CL
10 tháng 8 2016
\(\frac{7}{25}+\frac{18}{25}+\frac{4}{23}+\frac{5}{7}+\frac{19}{23}\)
\(=\left(\frac{7}{25}+\frac{18}{25}\right)+\left(\frac{4}{23}+\frac{19}{23}\right)+\frac{5}{7}\)
\(=1+1+\frac{5}{7}\)
\(=2+\frac{5}{7}=\frac{19}{7}\)
NT
0
HQ
Hà Quang Minh
Giáo viên
19 tháng 9 2023
a)
\(\begin{array}{l}\frac{{13}}{{23}}.\frac{7}{{11}} + \frac{{10}}{{23}}.\frac{7}{{11}}\\ = \frac{7}{{11}}.\left( {\frac{{13}}{{23}} + \frac{{10}}{{23}}} \right)\\ = \frac{7}{{11}}.\frac{23}{23}\\ = \frac{7}{{11}}.1\\ = \frac{7}{{11}}\end{array}\)
b)
\(\begin{array}{l}\frac{5}{9}.\frac{{23}}{{11}} - \frac{1}{{11}}.\frac{5}{9} + \frac{5}{9}\\ = \frac{5}{9}.\left( {\frac{{23}}{{11}} - \frac{1}{{11}} + 1} \right)\\ = \frac{5}{9}.\left( {2 + 1} \right)\\ = \frac{5}{9}.3 = \frac{5}{3}\end{array}\)
c)
\(\begin{array}{l}\left[ {\left( { - \frac{4}{9} + \frac{3}{5}} \right):\frac{{13}}{{17}}} \right] + \left( {\frac{2}{5} - \frac{5}{9}} \right):\frac{{13}}{{17}}\\ = \left( { - \frac{4}{9} + \frac{3}{5}} \right).\frac{{17}}{{13}} + \left( {\frac{2}{5} - \frac{5}{9}} \right).\frac{{17}}{{13}}\\ = \frac{{17}}{{13}}.\left( { - \frac{4}{9} + \frac{3}{5} + \frac{2}{5} - \frac{5}{9}} \right)\\ = \frac{{17}}{{13}}.\left[ {\left( { - \frac{4}{9} - \frac{5}{9}} \right) + \left( {\frac{3}{5} + \frac{2}{5}} \right)} \right]\\ =\frac{{17}}{{13}}. (\frac{-9}{9}+\frac{5}{5})\\= \frac{{17}}{{13}}.\left( { - 1 + 1} \right)\\ = \frac{{17}}{{13}}.0 = 0\end{array}\)
d)
\(\begin{array}{l}\frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{3}{{11}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{2}{5}} \right)\\ = \frac{3}{{16}}:\left( {\frac{3}{{22}} - \frac{6}{{22}}} \right) + \frac{3}{{16}}:\left( {\frac{1}{{10}} - \frac{4}{{10}}} \right)\\ = \frac{3}{{16}}:\frac{{ - 3}}{{22}} + \frac{3}{{16}}:\frac{{ - 3}}{{10}}\\ = \frac{3}{{16}}.\frac{{ - 22}}{3} + \frac{3}{{16}}.\frac{{ - 10}}{3}\\ = \frac{3}{{16}}.\left( {\frac{{ - 22}}{3} + \frac{{ - 10}}{3}} \right)\\ = \frac{3}{{16}}.\frac{{ - 32}}{3}\\ = - 2\end{array}\)
đáp án là -1.71428571429
23 : 7 - 5 =-1.71428571429