tìm x thuộc Z :
a, x - [( x - 7 ) + (x - 14 + 8 )] = 2x - 14
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a) Ta có: \(\left(2x-5\right)^3=216\)
\(\Leftrightarrow2x-5=6\)
\(\Leftrightarrow2x=11\)
hay \(x=\dfrac{11}{2}\)
b) Ta có: \(2x-3⋮x+4\)
\(\Leftrightarrow-11⋮x+4\)
\(\Leftrightarrow x+4\in\left\{1;-1;11;-11\right\}\)
hay \(x\in\left\{-3;-5;7;-15\right\}\)
Alo, sugeni two wai phem. Si ga no, you woo be the me that nas te, ai gi da
-2x - 40 = (5 - x) - (-15 + 60)
-2x - 40 = (5 - x) - 45
-2x - 40 = -40 - x
-2x - x = 40 - 40
-3x = 0
x = 0
2(x - 4) - 3(x + 7) = 14
2x - 8 - 3x - 21 = 14
-x - 29 = 14
-x = 14 + 29
-x = 43
x = -43
-7(5 - x) - 2(x - 10) = 15
-35 + 7x - 2x + 20 = 15
-15 + 5x = 15
5x = 15 + 15
5x = 30
x = 6
a) x - 14 = 3x + 18
=> x - 3x = 18 + 14
=> -2x = 32
=> x = 32 : (-2)
=> x = -16
b) 2(x - 5) - 3(x - 4) = -6 + 15.(-3)
=> 2x - 10 - 3x + 12 = -6 - 45
=> -x + 2 = -51
=> -x = -51 - 2
=> -x = -53
=> x = 53
c) (x + 7)(x - 9) = 0
=> \(\orbr{\begin{cases}x+7=0\\x-9=0\end{cases}}\)
=> \(\orbr{\begin{cases}x=-7\\x=9\end{cases}}\)
Vậy ...
d) |2x - 5| - 7 = 22
=> |2x - 5| = 22 + 7
=> |2x - 5| = 29
=> \(\orbr{\begin{cases}2x-5=29\\2x-5=-29\end{cases}}\)
=> \(\orbr{\begin{cases}2x=34\\2x=-24\end{cases}}\)
=> \(\orbr{\begin{cases}x=17\\x=-12\end{cases}}\)
Vậy ...
d) \(\left|2x-5\right|-7=22\)
\(\Rightarrow\left|2x-5\right|=22+7\)
\(\Rightarrow\left|2x-5\right|=29\)
\(\Rightarrow\orbr{\begin{cases}2x-5=29\\2x-5=-29\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}2x=34\\2x=-24\end{cases}}\) \(\Rightarrow\orbr{\begin{cases}x=17\\x=-12\end{cases}}\)
Vậy x = 17 hoặc x = -12
Ở câu b, bậc của y là bậc nhất nên có thể rút y theo x
\(y=\frac{112-2x^2+x}{2x+1}=\frac{-x\left(2x+1\right)+2x+1+111}{2x+1}=-x+1+\frac{111}{2x+1}\)
\(\Rightarrow2x+1\in\text{Ư}\left(111\right)=\left\{111;37;3;1;-111;-37;-3;-1\right\}\)
\(\Rightarrow x\in\left\{...\right\}\)
a) \(x+15=18-\left(-27\right)\)
\(\Leftrightarrow x+15=18+27\)
\(\Leftrightarrow x+15=45\)
\(\Leftrightarrow x=45-15\)
\(\Leftrightarrow x=30\)
b) \(-x+7=28\)
\(\Leftrightarrow-x=28-7\)
\(\Leftrightarrow-x=21\)
\(\Leftrightarrow x=-21\)
c) \(20-\left(-x\right)=14\)
\(\Leftrightarrow20+x=14\)
\(\Leftrightarrow x=14-20\)
\(\Leftrightarrow x=-6\)
d) \(2x+5=x-14\)
\(\Leftrightarrow2x+5-\left(x-14\right)=0\)
\(\Leftrightarrow2x+5-x+14=0\)
\(\Leftrightarrow x+19=0\)
\(\Leftrightarrow x=0-19\)
\(\Leftrightarrow x=-19\)
e) \(x+17=-8-20\)
\(\Leftrightarrow x+17=-\left(8+20\right)\)
\(\Leftrightarrow x+17=-28\)
\(\Leftrightarrow x=-28-17\)
\(\Leftrightarrow x=-\left(28+17\right)\)
\(\Leftrightarrow x=-45\)
f) \(3x+15=2x+6\)
\(\Leftrightarrow3x+15-\left(2x+6\right)=0\)
\(\Leftrightarrow3x+15-2x-6=0\)
\(\Leftrightarrow x+9=0\)
\(\Leftrightarrow x=0-9\)
\(\Leftrightarrow x=-9\)
Tìm x biết:
5. ( x-1 ) - 7.( x-2 ) = 2x -39
Tìm x thuộc Z biết:
x - 3 - 14.( x-2 )= -3x -3
\(3x+7⋮x-2\)
5 ( x - 1 ) - 7 ( x - 2 ) = 2x - 39
<=> 5x - 5 - 7x + 14 = 2x - 39
<=> 5x - 7x - 2x = -39 + 5 - 14
<=> -4x = -48
<=> x = 12
x - 3 - 14.( x-2 )= -3x -3\(\Rightarrow\chi-3-28-14\chi-28=-3\chi-3\)
\(\Rightarrow\chi-3-28+3=-3\chi-3\)
\(\Rightarrow\chi-28=11\chi\)
\(\Rightarrow\chi-11\chi=28\)
\(\Rightarrow10\chi=28\Rightarrow\chi=2,8\left(kot.m\chi\inℤ\right)\)
x - [( x - 7 ) + (x - 14 + 8 )] = 2x - 14
x - [ x - 7 + x - 14 + 8 ] = 2x - 14
x - x + 7 - x + 14 - 8 = 2x - 14
x - x - x - 2x = -14 - 7 - 14 + 8
-3x = -27
=> x = 9
Vậy...
Chúc em học tốt!!!
x = 9
#Pikachu:))#