(9/16)\(^{2016}\).(16/9)\(^{2015}\).4/3
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Những câu hỏi liên quan
23 tháng 10 2016
\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)
=\(\left(\frac{3}{4}\right)^{4032}.\left(\frac{4}{3}\right)^{4030}.\frac{4}{3}\)
=
29 tháng 6 2017
\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}=\left(\frac{9}{16}\right)^{2016}:\left(\frac{9}{16}\right)^{2015}.\frac{4}{3}\)
\(=\frac{9}{16}.\frac{4}{3}\)
\(=\frac{3}{4}\)
29 tháng 6 2017
\(\left(\frac{9}{16}\right)^{2016}\cdot\left(\frac{16}{9}\right)^{2015}\cdot\frac{4}{3}=\left(\frac{9}{16}\right)^{2016}\cdot\left(\frac{9}{16}\right)^{2015}\cdot\frac{4}{3}\)
\(=\frac{9}{16}\cdot\frac{4}{3}\)
\(=\frac{3}{4}\)
KK
25 tháng 11 2017
\(\left(\dfrac{9}{16}\right)^{2016}.\left(\dfrac{16}{9}\right)^{2015}.\dfrac{4}{3}\)
=\(\dfrac{9^{2016}}{16^{2016}}.\dfrac{16^{2015}}{9^{2015}}.\dfrac{4}{3}\)
= \(\dfrac{9}{16}.\dfrac{4}{3}=\dfrac{3^2.4}{4^2.3}=\dfrac{3}{4}\)
FB
tính
\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)
chỉ cần kết quả
3
NT
1
2 tháng 7 2017
=\(\frac{9^{2016}}{16^{2016}}.\frac{16^{2015}}{9^{2015}}.\frac{4}{3}\)
=\(\frac{9}{16}.\frac{4}{3}\)
=\(\frac{3}{4}\)
k cho mk nhoa
NH
2 tháng 7 2017
\(\left(\frac{9}{16}\right)^{2016}.\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)
\(=\left[\frac{9}{16}\left(\frac{9}{16}\right)^{2015}\right].\left(\frac{16}{9}\right)^{2015}.\frac{4}{3}\)
\(=\frac{9}{16}\left[\left(\frac{9}{16}\right)^{2015}.\left(\frac{16}{9}\right)^{2015}\right].\frac{4}{3}\)
\(=\frac{9}{16}\left[\left(\frac{9}{16}.\frac{16}{9}\right)^{2015}\right].\frac{4}{3}\)
\(=\frac{9}{16}.1^{2015}.\frac{4}{3}\)
\(=\frac{9}{16}.\frac{4}{3}\)
\(=\frac{3}{4}\)
30 tháng 9 2016
=(16/10)2015.(16/9)(4/3)
=(8/5)2015.(4/3)3
(bn xem lại đề, có thể là 9/16 chứ k phải là 9/10)?
NN
Nguyễn Ngọc Anh Minh
CTVHS
VIP
21 tháng 8 2023
a/
\(\dfrac{4}{15}=1-\dfrac{11}{15}\)
\(\dfrac{5}{16}=1-\dfrac{11}{16}\)
\(\dfrac{11}{15}>\dfrac{11}{16}\Rightarrow1-\dfrac{11}{15}< 1-\dfrac{11}{16}\Rightarrow\dfrac{4}{15}< \dfrac{5}{16}\)
b/
\(\dfrac{2}{113}=\dfrac{4}{226}< \dfrac{4}{115}\)
c/ \(\dfrac{2}{7}=\dfrac{4}{14}< \dfrac{4}{9}\)
d/ \(\dfrac{2}{5}=\dfrac{4}{10}< \dfrac{4}{7}\)
NM
21 tháng 8 2023
a,\(\dfrac{4}{15}< \dfrac{5}{16}\)
b,\(\dfrac{2}{113}< \dfrac{4}{115}\)
c,\(\dfrac{2}{7}< \dfrac{4}{9}\)
d,\(\dfrac{4}{7}>\dfrac{2}{5}\)
\(\left(\dfrac{9}{16}\right)^{2016}.\left(\dfrac{16}{9}\right)^{2015}.\dfrac{4}{3}\)
\(=\left[\left(\dfrac{3}{4}\right)^2\right]^{2016}.\left[\left(\dfrac{4}{3}\right)^2\right]^{2015}.\dfrac{4}{3}\)
\(=\left(\dfrac{3}{4}\right)^{2018}.\left(\dfrac{4}{3}\right)^{2017}.\dfrac{4}{3}\)
\(=\left(\dfrac{3}{4}\right)^{2018}.\left(\dfrac{4}{3}\right)^{2018}\)
\(=\left(\dfrac{3}{4}.\dfrac{4}{3}\right)^{2018}\)
\(=\left(\dfrac{1}{1}.\dfrac{1}{1}\right)^{2018}\)
\(=1^{2018}\)
\(=1\)