1 . 3.2x - 3 = 45
2 . 2448 : [ 119 - ( x - 6 ) ] = 0
3. 4x3 + 12 = 120
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3.2x—3=45
3.2x=45+3
3.2x=48
2x=48:3
2x=16
x=16:2
x=8
4x .3+12=120
4x.3=120–12
4x.3=108
4x=108:3
4x=36
x=36:4
x=9
\(3.2x-3=45\)
\(3.2x=45+3\)
\(3.2x=48\)
\(2x=\frac{48}{3}\)
\(2x=16\)
\(x=8\)
Vậy \(x=8\)
\(1500:\left[\left(36x+40\right):x\right]=30\)
\(\left(36x+40\right):x=1500:30\)
\(36x+40=50x\)
\(50x-36x=40\)
\(14x=40\)
\(x=\frac{40}{14}\)
\(x=\frac{20}{7}\)
Vậy \(x=\frac{20}{7}\)
Câu b,
= 50x + (1 + 3 + 5 + ..... + 99) = 2550
= 50x + 2500 = 2550
= 50x = 2550 - 2500
= 50x = 50
= x = 50 : 50
= x = 1
Trả lời
a)(136,5-x).1,2=5,4
136,5-x =5,4:1,2
136,5-x =4,5
x =136,5+4,5
x =141
b)18:(372:3.x-1)=6
372:3x-1 =18:6
372:3x-1 =3
372:3x =3+1
372:3x =4
3x =372:4
3x =93
x =93:3
x =31
c)[(6.x-39):7].4=12
(6x-39):7 =12:4
(6x-39):7 =3
6x-39 =3.7
6x-39 =21
6x =21+39
6x =60
x =60:6
x =10
d)2448:[119-(x-6)]=24
119-(x-6)=2448:24
119-(x-6)=102
x-6 =119-102
x-6 =17
x =17+6
x =23
Chúc bạn học tốt !
a, ( 136,5 - X ) x 1,2 = 5,4
=> 136,5 - X = 5,4 : 1,2
=> 136,5 - X = 4,5
=> X = 136,5 - 4,5
=> X = 132
b, hình như sai đề bạn ơi
c, [ ( 6 x X - 39 ) : 7 ] x 4 = 12
=> ( 6 x X - 39 ) : 7 = 12 : 4
=> ( 6 x X - 39 ) :7 = 3
=> 6 x X - 39 = 3 x 7
=> 6 x X - 39 = 21
=> 6 x X = 60
=> X = 60 : 6
=> X = 10
d, 2448 : [ 119 - ( x - 6 ) ] = 24
=> 119 - ( x - 6 ) = 2448 : 24
=> 119 - ( x - 6 ) = 102
=> x - 6 = 119 - 102
=> x - 6 = 17
=> x = 17 + 6
=> x = 23
Mình không chép lại đề nha
a)119-(x-6)=102
x-6 =17
x =23
b)(6x-39):7=3
6x-39 =21
6x =60
x =10
c, d bạn tự làm nha
1) 25 + 91 + 75 + 101
= (25+75) + (91 + 101)
= 100 + 192
= 292
2) 41 x 39 - 41 x 9
= 41 x (39 - 9)
= 41 x 30
= 1230
3) 710 x 99 + 710
= 710 x 99 + 710 x 1
= 710 x (99 + 1)
= 710 x 100
= 71000
4) 17 x 85 + 15 x 17 - 120
= 17 x (85 + 15) - 120
= 17 x 100 -120
= 1700 -120
= 1580
5) (39 x 42 - 37 x 42) : 42
= 42 x (39 - 37) : 42
= 42 x 2 : 42
= 84 : 42
=2
6) 120 - 48 - 52
= 120 - (48 + 52)
= 120 - 100
= 20
7) 23 x 75 + 25 x 23 + 180
= 23 x (75 + 25) +180
= 23 x (75 + 25) +180
= 23 x 100 + 180
= 2300 +180
=2480
8) 2448 : [119 - (23 - 6)]
= 2448 : (119 - 17)
= 2448 : 102
= 24
a) (x+12)-20=0
x+12=20
x=8
b) 5.(x-7)=0
x-7=0
x=7
c) 12x-3x+1=937
12x-3x=936
9x=936
x=104
d) 2448 : [ 119 - ( x - 6 ) ] = 24
119-(x-6) = 102
x-6=17
x=23
a ) ( x + 12 ) - 20 = 0
x + 12 = 0 + 20
x +12 = 20
x = 20 - 12
x = 8
b ) 5 . ( x - 7 ) =0
x - 7 = 0 : 5
x - 7 = 0
x = 0 + 7
x = 7
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
`2448:[119-(x-6)]=24`
`=>119-(x-6)= 2448 : 24`
`=>119-(x-6)= 102`
`=> x-6=119-102`
`=> x-6=17`
`=>x=17+6`
`=>x=23`
\(2448:\left[119-\left(x-6\right)\right]=24\)
\(119-\left(x-6\right)=2448:24\)
\(119-\left(x-6\right)=102\)
\(x-6=119-102\)
\(x-6=17\)
\(x=17+6\)
\(x=23\)( thỏa mãn \(x\in N\) )
vậy x = 23
\(2016-100\cdot\left(x+11\right)=2^7:2^3\)
\(2016-100\cdot\left(x+11\right)=128:8\)
\(2016-100\cdot\left(x+11\right)=16\)
\(100\cdot\left(x+11\right)=2016-16\)
\(100\cdot\left(x+11\right)=2000\)
\(x+11=2000:100\)
\(x+11=20\)
\(x=20-11\)
\(x=9\)( thỏa mãn \(x\in N\))
vậy x = 9
a: Ta có: \(10-\left\{\left[\left(x:3+17\right):10+3\cdot2^4\right]:10\right\}=5\)
\(\Leftrightarrow\left[\left(x:3+17\right):10+48\right]:10=5\)
\(\Leftrightarrow\left(x:3+17\right):10+48=50\)
\(\Leftrightarrow\left(x:3+17\right):10=2\)
\(\Leftrightarrow x:3+17=20\)
\(\Leftrightarrow x:3=3\)
hay x=9
b: Ta có: \(2448:\left[119-\left(x-6\right)\right]=24\)
\(\Leftrightarrow119-\left(x-6\right)=102\)
\(\Leftrightarrow x-6=17\)
hay x=23
c: Ta có: \(165-\left(35:x+3\right)\cdot19=13\)
\(\Leftrightarrow\left(35:x+3\right)\cdot19=152\)
\(\Leftrightarrow\left(35:x+3\right)=8\)
\(\Leftrightarrow35:x=5\)
hay x=7
1 . 3.2x - 3 = 45
3.2x=45+3
3.2x=48
2x=48:3
2x=16
2x=24
vậy=4
2 . 2448 : [ 119 - ( x - 6 ) ] = 0
119 - ( x - 6 ) = 2448:0
119 - ( x - 6 ) = 0
x-6=0+119
x-6=199
x=199+6
x= 205
3. 4x3 + 12 = 120
4x3 =120-12
4x3 = 108
x3=108:4
x3=27
x3=33
vẫy=3