Question

[tran dinh viet]

viet ket qua phep tinh duoi dang luy thua

a, 4^2-8^5

b, 27^3.9^4

c, 64^3.167

Answer 1

[Hắc Hường]

Giải:

a) \(4^2.8^5=\left(2^2\right)^2.\left(2^3\right)^5=2^4.2^{15}=2^{19}\)

b) \(27^3.9^4=\left(3^3\right)^3.\left(3^2\right)^4=3^9.3^8=3^{17}\)

c) \(64^3.16^7=\left(4^3\right)^3.\left(4^2\right)^7=4^9.4^{14}=4^{23}\)