96 - 3(x+1) = 42
Giúp vs ah
K
Khách
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2 tháng 12 2021
\(A=\left(2+2^2+2^3+2^4+2^5+2^6\right)+...+\left(2^{2017}+2^{2018}+2^{2019}+2^{2020}+2^{2021}+2^{2022}\right)\\ A=\left(2+2^2+2^3+2^4+2^5+2^6\right)\left(1+...+2^{2017}\right)\\ A=126\left(1+...+2^{2017}\right)⋮42\left(126⋮42\right)\)
NN
5
4 tháng 4 2021
A=\(\dfrac{1}{1.2}+\dfrac{1}{2.3}+\dfrac{1}{3.4}+\dfrac{1}{4.5}+\dfrac{1}{5.6}+\dfrac{1}{6.7}-\dfrac{1}{20}\)
\(=\dfrac{2-1}{1.2}+\dfrac{3-2}{2.3}+\dfrac{4-3}{3.4}+\dfrac{5-4}{4.5}+\dfrac{6-5}{5.6}+\dfrac{7-6}{6.7}-\dfrac{1}{20}\)
\(=1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{6}+\dfrac{1}{6}-\dfrac{1}{7}-\dfrac{1}{20}\)
\(=1-\dfrac{1}{7}-\dfrac{1}{20}=1-\dfrac{27}{140}=\dfrac{113}{140}\)
QT
3
VT
20 tháng 2 2023
\(\dfrac{6}{36}+\dfrac{5}{6}=\dfrac{1}{6}+\dfrac{5}{6}=\dfrac{6}{6}=1\\ \dfrac{1}{4}+\dfrac{5}{30}=\dfrac{1}{4}+\dfrac{1}{6}=\dfrac{6}{24}+\dfrac{4}{24}=\dfrac{10}{24}=\dfrac{5}{12}\\ \dfrac{5}{56}+\dfrac{3}{21}=\dfrac{5}{56}+\dfrac{1}{7}=\dfrac{5}{56}+\dfrac{8}{56}=\dfrac{13}{56}\\\dfrac{12}{18}+\dfrac{12}{42}=\dfrac{2}{3}+\dfrac{2}{7}=\dfrac{14}{21}+\dfrac{6}{21}=\dfrac{20}{21} \)
VQ
20 tháng 2 2023
6/36 + 5/6=1/6+5/6=6/6=1
1/4 + 5/30=1/4+1/6=6/24+4/24=10/24=5/12
5/56 + 3/21=5/56=1/7=5/56+8/56=13/56
12/18 + 12/42=2/3+2/7=14/21+6/21=20/21
MT
1
Đây bn nhé . Học tốt !
12 tháng 8 2023
\(M=\left(\dfrac{3}{\sqrt{x}+3}+\dfrac{x+9}{x-9}\right):\left(\dfrac{2\sqrt{x}-5}{x-3\sqrt{x}}-\dfrac{1}{\sqrt{x}}\right)\)
\(=\dfrac{3\sqrt{x}-9+x+9}{x-9}:\dfrac{2\sqrt{x}-5-\sqrt{x}+3}{\sqrt{x}\left(\sqrt{x}-3\right)}\)
\(=\dfrac{x+3\sqrt{x}}{x-9}\cdot\dfrac{\sqrt{x}\left(\sqrt{x}-3\right)}{\sqrt{x}-2}\)
\(=\dfrac{x\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)}{\left(\sqrt{x}-3\right)\left(\sqrt{x}+3\right)\left(\sqrt{x}-2\right)}=\dfrac{x}{\sqrt{x}-2}\)
A
1
20 tháng 1 2020
\(\Leftrightarrow\) x-96+12 = 34-x
\(\Leftrightarrow\) x-84 =34-x
\(\Leftrightarrow\) 2x=118
\(\Rightarrow\) x=59
Vậy x=59
92 - 3(x+1) = 42
3(x+1) = 50
x+1 = 50/3
x = 47/3
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