Tìm phân số bằng nhau: 2/9;10/35;4/3;10/45;24/108;20/70;4/6;14/49
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$\frac{2}{3} = \frac{{2 \times 3}}{{3 \times 3}} = \frac{6}{9}$
$\frac{3}{4} = \frac{{3 \times 3}}{{4 \times 3}} = \frac{9}{{12}}$
Vậy $\frac{2}{3} = \frac{6}{9}$ ; $\frac{3}{4} = \frac{9}{{12}}$
\(\dfrac{2}{3}=\dfrac{6}{9}\)
\(\dfrac{3}{4}=\dfrac{9}{12}\)
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\(\dfrac{5}{7}=\dfrac{70}{98};\dfrac{2}{5}=\dfrac{14}{35};\dfrac{1}{8}=\dfrac{9}{72};\dfrac{120}{80}=\dfrac{3}{2}\)
\(\dfrac{5}{7}=\dfrac{70}{98}\)
\(\dfrac{2}{5}=\dfrac{14}{35}\)
\(\dfrac{1}{8}=\dfrac{9}{72}\)
\(\dfrac{120}{80}=\dfrac{3}{2}\)
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Tham khảo:
Như vậy,\(\dfrac{2}{5} = \dfrac{4}{{10}}\)
\(\dfrac{1}{3} = \dfrac{3}{9}\)
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1)\(\frac{2}{9}=0,\left(2\right)\)
\(\frac{3}{9}=0,\left(3\right)\)
2) a) 0,1234567
b) 10,2345
c) 12,034
1 >
\(\frac{2}{9}=0,222...=0,\left(2\right)\)
\(\frac{3}{9}=0,333...=0,\left(3\right)\)
2>
a) \(0,1234567\)
b) \(10,2345\)
c)\(10,234\)
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TL
các P/s bằng nhau là
3/4=36/48; 9/13=54/78=108/256; 5/7=75/105; 2/9=42/189.
nha bn
HT
TL:
\(\frac{3}{4}=\frac{36}{48}\)
\(\frac{2}{9}=\frac{42}{189}\)
\(\frac{5}{7}=\frac{75}{105}\)
\(\frac{9}{13}=\frac{108}{156}\)
Còn dư phân số : 54/78
_HT_
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`-18/22=(-18 \div 2)/(22 \div 2)=-9/11 -> -18/22= -9/11`
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C1 :Coi các số cần tìm là x : 4/9 < x < 6/11 => 44/99< x < 54 / 99
C2 : Công thức : a/b < a+c / b+d < c/d
2/9 = 14/49
10/35 = 20/70
Đừng k sai mình nhé !
2/9=10/45 ; 20/70= 10/35 ; 4/6= 24/108 ; 4/3= ? ( lỗi đề)
đúng ko
k mk nhé
Mio