tìm x biết 3 nhân x - 15 = 32
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![](https://rs.olm.vn/images/avt/0.png?1311)
![](https://rs.olm.vn/images/avt/0.png?1311)
x + 5 x 2 - ( 32 + 16 x 3 : 6 - 15 ) = 0
x + 5 x 2 - 25 = 0
x + 5 x 2 = 0 + 25
x + 5 x 2 = 25
x + 10 = 25
x = 25 - 10
x = 15
![](https://rs.olm.vn/images/avt/0.png?1311)
bài 1
16*25*5*125*2*12
=16*125*125*24
=16*(125*125)*24
=16*15625*24
=6000000
bài 2
a) x+37=121
x =121-37
x =84
b) 31+x+29=189
31+x =189-29
31+x = 160
c)129+x=170
x =170-129
x= 41
d) x-32*27=0
x-32 =0:27
x-32 =0
x =0+32
x =32
e)(x-3)*14=28
x-3 =28:14
x-3 =2
x =2+3
x =5
f) 15*x+2=45
15*x =45-2
15*x =43
x =43:15
x =\(\frac{43}{15}\)
g) (39-x)*32=32
39-x =32:32
39-x =1
x =39-1
x =38
h) (x-27)-145=0
x-27 =0+145
x-27 =145
x =145+27
x =172
chúc bạn học tốt
![](https://rs.olm.vn/images/avt/0.png?1311)
\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)
Đặt \(A=\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...+\frac{20}{53.55}\)
\(A=\frac{10.2}{11.13}-\frac{10.2}{13.15}-\frac{10.2}{15.17}-...-\frac{10.2}{53.55}\)
\(A=10\left(\frac{2}{11.13}-\frac{2}{13.15}-\frac{2}{15.17}-...-\frac{2}{53.55}\right)\)
\(A=10\left(\frac{1}{11}-\frac{1}{55}\right)\)
\(A=10.\frac{4}{55}\)
\(A=\frac{40}{55}\)\(A=10.\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)\)
![](https://rs.olm.vn/images/avt/0.png?1311)
i) xy - 6y + 2x - 12
= (xy - 6y) + (2x - 12)
= y(x - 6) + 2(x - 6)
= (x - 6)(y + 2)
ii) 2x(y - z) + (z - y)(x + y)
= 2x(y - z) - (y - z)(x + y)
= (y - z)(2x - x - y)
= (y - z)(x - y)
b) x + 3 = (x + 3)2 ⇔ (x + 3)2 - (x + 3) = 0 ⇔ (x + 3)(x + 3 - 1) = 0
⇔ (x + 3)(x + 2) = 0
Vậy x = -3; x = -2
![](https://rs.olm.vn/images/avt/0.png?1311)
a) x + 15 = 32
x = 32 - 15
x = 17
b) x - 32 = 45
x = 45 + 32
x = 77
![](https://rs.olm.vn/images/avt/0.png?1311)
1)\(x-105:21=15\)
\(x-5=15\)
\(x=15+5\)
\(x=20\)
Vậy \(x=20.\)
2)\(\left(x-105\right):21=15\)
\(\left(x-105\right)=15.21\)
\(x-105=315\)
\(x=315+105\)
\(x=420\)
Vậy \(x=412.\)
4)\(1818:\left(6x-37\right)=18\)
\(6x-37=1818:18\)
\(6x-37=101\)
\(6x=101+37\)
\(6x=138\)
\(x=138:6\)
\(x=23\)
Vậy \(x=23.\)
3X=32+15
3X=47
X=47:3
X=\(\frac{47}{3}\)
Đề bài chia bị dư nhé bn
Bn xem lại đề đi nhé
K mk nha
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