10,42 : ( 21,34 - \(\frac{1}{2}\)) + \(\frac{2}{3}\) . . 75 %
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ND
1
MT
12 tháng 8 2015
\(10,42:\left(21,34-50\%\right)+\frac{2}{3}\times0,75\)
\(=\frac{1042}{100}:\left(\frac{2134}{100}-\frac{50}{100}\right)+\frac{2}{3}\times\frac{75}{100}\)
\(=\frac{521}{50}:\left(\frac{1067}{50}-\frac{1}{2}\right)+\frac{2}{3}\times\frac{3}{4}\)
\(=\frac{521}{50}:\left(\frac{1067}{50}-\frac{25}{50}\right)+\frac{1}{2}\)
\(=\frac{521}{50}:\frac{1042}{50}+\frac{1}{2}\)
\(=\frac{521}{50}\times\frac{50}{1042}+\frac{1}{2}\)
\(=\frac{1}{2}+\frac{1}{2}=1\)
TM
5
18 tháng 8 2019
=\(\frac{1}{2}.\frac{2\sqrt{3}}{9}-\frac{2\sqrt{3}}{5}+\frac{2\sqrt{3}}{3}\)
=\(\frac{\sqrt{3}}{9}-\frac{2\sqrt{3}}{5}+\frac{2\sqrt{3}}{3}\)
=\(\frac{5\sqrt{3}}{45}-\frac{18\sqrt{3}}{45}+\frac{30\sqrt{3}}{45}\)
=\(\frac{17\sqrt{3}}{45}\)
27 tháng 4 2019
\(=\frac{75}{100}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\left(-\frac{1}{3}\right)^2\)
\(=\frac{3}{4}-\frac{3}{2}+\frac{6}{5}-\frac{1}{9}\)
\(=\frac{-3}{4}+\frac{6}{5}-\frac{1}{9}\)
\(=\frac{9}{20}-\frac{1}{9}\)
\(=\frac{61}{180}\)
27 tháng 4 2019
\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)
= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{-1}{8}\)
= \(\frac{3}{4}-\frac{6}{4}+\frac{1}{2}\cdot\frac{12}{5}-\frac{-1}{8}\)
= \(-\frac{3}{4}+\frac{6}{5}-\frac{-1}{8}=\frac{-30}{40}+\frac{48}{40}+\frac{-6}{40}=\frac{12}{40}=\frac{3}{10}\)
CHÚC BN HK TỐT #
VT
27 tháng 4 2019
\(=-\frac{3}{4}+\frac{6}{5}-\left(\frac{-1}{8}\right)\))
=\(-\frac{3}{4}+\frac{6}{5}+\frac{1}{8}\)
=\(\frac{9}{20}+\frac{1}{8}\)
=\(\frac{23}{40}\)
Vậy..........
27 tháng 4 2019
\(\frac{75}{100}-1\frac{1}{2}+0,5:\frac{5}{12}-\left(-\frac{1}{2}\right)^3\)
= \(\frac{3}{4}-\frac{3}{2}+\frac{6}{5}+\frac{1}{8}\)
= \(\frac{30}{40}-\frac{60}{40}+\frac{48}{40}+\frac{5}{40}\)
= \(\frac{23}{40}\)
HN
24 tháng 4 2018
\(\left(\frac{x}{-5}+1\frac{1}{2}\right):\frac{28}{75}-1,4.\frac{15}{49}=\left|-\frac{2}{3}\right|.\left(-\frac{3}{2}\right)^3\)
\(\left(\frac{x}{-5}+\frac{3}{2}\right).\frac{75}{28}-\frac{14}{10}.\frac{15}{49}=\frac{2}{3}.\frac{-27}{8}\)
\(\left(\frac{-x}{5}+\frac{3}{2}\right).\frac{75}{28}-\frac{3}{7}=\frac{-9}{4}\)
\(\left(\frac{-x}{5}+\frac{3}{2}\right).\frac{75}{28}=\frac{-9}{4}+\frac{3}{7}\)
\(\left(\frac{-x}{5}+\frac{3}{2}\right).\frac{75}{28}=\frac{-63}{28}+\frac{12}{28}\)
\(\left(\frac{-x}{5}+\frac{3}{2}\right).\frac{75}{28}=\frac{-51}{28}\)
\(\frac{-x}{5}+\frac{3}{2}=\frac{-51}{28}:\frac{75}{28}\)
\(\frac{-x}{5}+\frac{3}{2}=\frac{-51}{28}.\frac{28}{75}\)
\(\frac{-x}{5}+\frac{3}{2}=\frac{-17}{25}\)
\(\frac{-x}{5}=\frac{-17}{25}-\frac{3}{2}\)
\(\frac{-x}{5}=\frac{-34}{50}-\frac{75}{50}\)
\(\frac{-x}{5}=\frac{-109}{50}\)
\(\frac{-10x}{50}=\frac{-109}{50}\)
Hình như đề sai thì phải
10,42 : (21,34 - \(\frac{1}{2}\))+\(\frac{2}{3}\).75%
=10,42 : 20,84 +\(\frac{2}{3}\).75%
=\(\frac{1}{2}\)+\(\frac{2}{3}\).75:100
=\(\frac{1}{2}\)+50:100
=\(\frac{1}{2}\)+\(\frac{1}{2}\)=1