1+2y/18=1+4y/24=1+6y/6x
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2 tháng 9 2023
(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x
=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5
2 tháng 9 2023
(1+2y)/18=(1+6y)/6x=(1+2y+1+6y)/18+6x=(2+8y)/18+6x=(1+4y)/9+3x
=>(1+4y)/9+3x=(1+4y)/24 =>9+3x=24 =>3x=15 =>x=5
Nhé bạn !
HP
3 tháng 2 2016
xét:\(\frac{1+2y}{18}=\frac{1+6y}{6x}=\frac{1+2y+1+6y}{18+6x}=\frac{2+8y}{18+6x}=\frac{2\left(1+4y\right)}{2\left(9+3x\right)}=\frac{1+4y}{9+3x}\) (t/c dãy tỉ số=nhau)
=>\(\frac{1+4y}{24}=\frac{1+4y}{9+3x}\Rightarrow24=9+3x\Rightarrow x=5\)
vậy x=5 thỏa mãn
LM
3 tháng 2 2016
Ta có: 1 + 2y/18 = 1 + 4y/24 = 1 + 6y/6x = 1 + 2y + 1 + 6y/18 + 6x = 2 + 8y/18 + 6x = 2(1 + 4y)/18 + 6x
\ 18 + 6x = 2 . 24 = 48
\ 6x = 30
\ x = 5
15 tháng 3 2017
Ta có: \(\dfrac{1+2y}{18}=\dfrac{1+4y}{24}\)
\(\Rightarrow\) 24 . (1 + 2y) = 18 . (1 + 4y)
\(\Rightarrow\) 24 + 48y = 18 + 72y
\(\Rightarrow\) 24 - 18 = 72y - 48y
\(\Rightarrow\) 6 = 24y
\(\Rightarrow\) y = \(\dfrac{1}{4}\)
Thay y = \(\dfrac{1}{4}\) ta có:
\(\dfrac{1+1}{24}=\dfrac{1+\dfrac{3}{2}}{6x}\)
\(\Rightarrow\) \(\dfrac{1}{12}=\dfrac{\dfrac{5}{2}}{6x}\)
\(\Rightarrow\) \(6x=\dfrac{5}{2}.12\)
\(\Rightarrow\) \(6x=30\)
\(\Rightarrow\) \(x=5\)
Vậy x = 5 và y = \(\dfrac{1}{4}\)
21 tháng 5 2022
\(\left\{{}\begin{matrix}\dfrac{2y+1}{18}=\dfrac{4y+1}{24}\\\dfrac{4y+1}{24}=\dfrac{6y+1}{6x}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}4\left(2y+1\right)=3\left(4y+1\right)\\\dfrac{4y+1}{4}=\dfrac{6y+1}{x}\end{matrix}\right.\)
\(\Leftrightarrow\left\{{}\begin{matrix}12y+3-8y-4=0\\\dfrac{4y+1}{4}=\dfrac{6y+1}{x}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=\dfrac{1}{4}\\\dfrac{2}{4}=\dfrac{\dfrac{3}{2}+1}{x}\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}y=\dfrac{1}{4}\\\dfrac{5}{2}:x=\dfrac{1}{2}\end{matrix}\right.\Leftrightarrow\left(x,y\right)=\left(5;\dfrac{1}{4}\right)\)
30 tháng 6 2021
ta co : 1+2y/18=1+4y/24
=> 24(1+2y)=18(1+4y)
=>24+48y=18+72y
=>24-18=72y-48y
=>6=24y
=>y=1/4
thay y thanh 1/4 vao de bai ta co :
1+1/2/18=1+1/24=(1+3/2)/6x
=>1/12=(5/2)/6x
=>12/(5/2)=6x
=>30=6x/x=5
vay x=5 va y=1/4
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Ta có:
\(\frac{1+2y}{18}=\frac{1+4y}{24}\Leftrightarrow24+48y=18+72y\Leftrightarrow y=\frac{1}{4}\Rightarrow\frac{1+4y}{24}=\frac{1}{12}\).
\(\frac{1+6y}{6x}=\frac{1}{12}\Leftrightarrow x=2\left(1+6y\right)=2\left(1+\frac{3}{2}\right)=5\).
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
Ta có :
\(\frac{1+2y}{18}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
\(\Rightarrow\frac{1+4y}{24}=\frac{1+2y+1+6y}{18+6x}\)
\(\Rightarrow\frac{1+4y}{24}=\frac{2+8y}{2\left(9+3x\right)}\)
\(\Rightarrow9+3x=24\)
\(3x=15\)
\(\Rightarrow x=5\)