Tìm GTNNA= x2 + y2 – 6x + 4y + 20B= 9x2 + y2 + 2z2 – 18x + 4z – 6y +30C= x2 +y2 + z2 – xy – yz – zx + 3D= 5x2 + 2y2 + 4xy – 2x + 4y + 2021E= x2 – 2x+ 4y2 + 4y + 2014F= 5x2 + 5y2 + 8xy + 2y – 2x + 30K= x2 + 4y2 + z2 – 2x + 12y – 4z +44Giúp mik vs cần...
Đọc tiếp
Tìm GTNN
A= x2 + y2 – 6x + 4y + 20
B= 9x2 + y2 + 2z2 – 18x + 4z – 6y +30
C= x2 +y2 + z2 – xy – yz – zx + 3
D= 5x2 + 2y2 + 4xy – 2x + 4y + 2021
E= x2 – 2x+ 4y2 + 4y + 2014
F= 5x2 + 5y2 + 8xy + 2y – 2x + 30
K= x2 + 4y2 + z2 – 2x + 12y – 4z +44
Giúp mik vs cần gấp!!!!
$A=x^2+y^2-6x+4y+20=(x^2-6x+9)+(y^2+4y+4)+7$
$=(x-3)^2+(y+2)^2+7\geq 0+0+7=7$
Vậy $A_{\min}=7$. Giá trị này đạt tại $(x-3)^2=(y+2)^2=0$
$\Leftrightarrow x=3; y=-2$
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$B=9x^2+y^2+2z^2-18x+4z-6y+30$
$=(9x^2-18x+9)+(y^2-6y+9)+(2z^2+4z+2)+10$
$=9(x^2-2x+1)+(y^2-6y+9)+2(z^2+2z+1)+10$
$=9(x-1)^2+(y-3)^2+2(z+1)^2+10\geq 10$
Vậy $B_{\min}=10$. Giá trị này đạt tại $(x-1)^2=(y-3)^2=(z+1)^2$
$\Leftrightarrow x=1; y=3; z=-1$
$C=x^2+y^2+z^2-xy-yz-xz+3$
$2C=2x^2+2y^2+2z^2-2xy-2yz-2xz+6$
$=(x^2-2xy+y^2)+(y^2-2yz+z^2)+(x^2-2xz+z^2)+6$
$=(x-y)^2+(y-z)^2+(z-x)^2+6\geq 6$
$\Rightarrow C\geq 3$
Vậy $C_{\min}=3$. Giá trị này đạt tại $x-y=y-z=z-x=0$
$\Leftrihgtarrow x=y=z$
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$D=5x^2+2y^2+4xy-2x+4y+2021$
$=2(y^2+2xy+x^2)+3x^2-2x+4y+2021$
$=2(x+y)^2+4(x+y)+3x^2-6x+2021$
$=2(x+y)^2+4(x+y)+2+3(x^2-2x+1)+2016$
$=2[(x+y)^2+2(x+y)+1]+3(x^2-2x+1)+2016$
$=2(x+y+1)^2+3(x-1)^2+2016\geq 2016$
Vậy $D_{\min}=2016$ khi $x+y+1=x-1=0$
$\Leftrightarrow x=1; y=-2$