120+25*3=(x+23):4
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1)
a) 2x + 5 = 3⁴ : 3²
2x + 5 = 3²
2x + 5 = 9
2x = 9 - 5
2x = 4
x = 4 : 2
x = 2
b) (3x - 24).73 = 2.74
(3x - 24).73 = 148
3x - 24 = 148/73
3x = 148/73 + 24
3x = 1900/73
x = 1900/73 : 3
x = 1900/219
c) [3.(42 - x)] + 15 = 23.3
126 - 3x + 15 = 69
141 - 3x = 69
3x = 141 - 69
3x = 72
x = 72 : 3
x = 24
d) 126 + (132 - x) = 300
132 - x = 300 - 126
132 - x = 174
x = 132 - 174
x = -42
2)
a) 120 - (x + 55) = 60
x + 55 = 120 - 60
x + 155 = 60
x = 60 - 55
x = 5
b) (7x - 11).3 = 25.52 + 200
(7x - 11).3 = 1500
7x - 11 = 1500 : 3
7x - 11 = 500
7x = 500 + 11
7x = 511
x = 511 : 7
x = 73
c) 2x + 2x + 4 = 544
4x = 544 - 4
4x = 540
x = 540 : 4
x = 135
cau1 :120-(100+x)=25
100+x=120-25
100+x=95
x=-5
cau2: 5(x+23)+6=96
5(x+23)+6=96
5(x+23)=90
x+23=18
x=-5
cau3: 100-(25+x)=40
25+x=100-40
25+x=60
x=35
cau4: 35-9(x+2)=45
9(x+2)=-10
x+2=-10/9
x=-28/9
23 + 23 x 2 + 23 x 3 + 23 x 4
= 23 x (1 + 2 + 3 + 4)
= 23 x 10
= 230
246 x 2005 - 2005 x 148
= (246 - 148) x 2005
= 98 x 2005
= 196490
25 x 12 x 30 x 4
= (25 x 4) x 12 x 30
= 100 x 360
= 36000
\(a.\dfrac{12+x}{42}=\dfrac{35}{42}\Leftrightarrow12+x=35\Leftrightarrow x=23\)
\(b.\dfrac{25-x}{40}=\dfrac{3}{8}\Leftrightarrow\dfrac{25-x}{40}=\dfrac{15}{40}\Leftrightarrow25-x=15\Leftrightarrow x=10\)
\(c.\dfrac{13+x}{20}=\dfrac{3}{4}\Leftrightarrow\dfrac{13+x}{20}=\dfrac{15}{20}\Leftrightarrow13+x=15\Leftrightarrow x=2\)
\(d.\dfrac{23-x}{25}=\dfrac{20}{25}\Leftrightarrow23-x=20\Leftrightarrow x=3\)
a. 246 x 2005 - 2005 x 148
= (246 - 148) x 2005
= 98 x 2005
= 196490
b. 25 x 12 x 30 x 4
= (25 x 4) x 12 x 30
= 100 x 360
= 36000
c. 23 + 23 x 2 + 23 x 3 + 23 x 4
= 23 x 1 + 23 x 2 + 23 x 3 + 23 x 4
= 23 x (1 + 2 + 3 + 4)
= 23 x 10
= 230
TL:
8/15 x 5/6 = 40/90 = 4/9
41/20 x 3/4 = 123/80
(11/23 + 9/23) + (18/23 + 2/23) = 20/23 + 20/23 = 40/43
HT
\(\left(\frac{2}{3}\times\frac{4}{5}\right)\times\frac{5}{6}\) = \(\frac{2}{3}\times\frac{4}{5}\times\frac{5}{6}\)=\(\frac{2\times4\times5}{3\times5\times6}\)=\(\frac{2\times4\times5}{3\times5\times2\times3}\)=\(\frac{4}{9}\)
\(\frac{11}{23}+\frac{2}{23}+\frac{9}{23}+\frac{18}{23}\)=\(\frac{\left(11+9\right)+\left(18+2\right)}{23}\)=\(\frac{20+20}{23}\)=\(\frac{40}{23}\)
\(\frac{27}{12}+\frac{17}{6}-\frac{25}{36}-\frac{15}{6}\)=\(\left(\frac{27}{12}-\frac{25}{36}\right)+\left(\frac{17}{6}-\frac{15}{6}\right)\)=\(\frac{14}{9}+\frac{2}{6}\)=\(\frac{17}{9}\)
/HT\
128 - 3 .(x+4) =23
3.(x+4)=128-23
3.(x+4)=105
x+4=105:3
x+4=35
x=35-4
x=31
(7 - x) -( 25 +7)=-25
(7 -x)-32=-25
7-x=-25+32
7-x=7
x=7-7
x=0
120 + 25 x 3 = ( x + 23 ) : 4
120 + 75 = ( x + 23 ) : 4
195 x 4 = x + 23
x + 23 = 780
x = 780 - 23 = 757
\(120+25.3=\left(x+23\right):4\)
\(120+75=\left(x+23\right):4\)
\(195.4=x+23\)
\(\Rightarrow780=x+23\)
\(\Rightarrow x=757\)