Tìm x:
(x.0,5-3/7): 1/2=
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a, \(\left(\dfrac{1}{2}+\dfrac{4}{7}\right):x=\dfrac{-3}{4}\)
\(\dfrac{15}{14}:x=\dfrac{-3}{4}\)
=> x= \(\dfrac{-7}{10}\)
b, 0,5:x-\(1\dfrac{3}{4}\)= 25%
0,5:x-\(\dfrac{7}{4}=\dfrac{1}{4}\)
0,5:x = 2
=> x = \(\dfrac{1}{4}\)
a) 9x-1/4=3/2
=>9x=3/2+1/4
=>9x=7/4
=>x=7/4:9
=>x=7/36
Vậy x=7/36
b)(4x+2):2,5=3,2:0,5
=>(4x+2):2,5=6,4
=>4x+2=6,4.2,5
=>4x+2=16
=>4x=16-2
=>4x=14
=>x=14:4
=>x=7/2
Vậy x=7/2
c) 5,4/x-2=6/7
=>5,4/x=6/7+2
=>5,4/x=20/7
=>x=5,4 :20/7
=>x=1,89
Vậy x= 1,89
d) 0,5:2=3:(2x+7)
=>3:(2x+7)=0,25
=>2x+7=3:0,25
=>2x+7=12
=>2x=12-7
=>2x=5
=>x=5/2
Vậy x=5/2
a) 9x-1/4=3/2
=>9x=3/2+1/4
=>9x=7/4
=>x=7/4:9
=>x=7/36
Vậy x=7/36
b)(4x+2):2,5=3,2:0,5
=>(4x+2):2,5=6,4
=>4x+2=6,4.2,5
=>4x+2=16
=>4x=16-2
=>4x=14
=>x=14:4
=>x=7/2
Vậy x=7/2
c) 5,4/x-2=6/7
=>5,4/x=6/7+2
=>5,4/x=20/7
=>x=5,4 :20/7
=>x=1,89
Vậy x= 1,89
d) 0,5:2=3:(2x+7)
=>3:(2x+7)=0,25
=>2x+7=3:0,25
=>2x+7=12
=>2x=12-7
=>2x=5
=>x=5/2
Vậy x=5/2
1) \(2x^2+5x-3=0\)
\(\Leftrightarrow2x^2+6x-x-3=0\)
\(\Leftrightarrow2x\left(x+3\right)-\left(x+3\right)=0\)
\(\Leftrightarrow\left(x+3\right)\left(2x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x+3=0\\2x-1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=-3\\x=\frac{1}{2}\end{cases}}}\)
\(2x^2+5x-3=0\)
\(\Leftrightarrow2x^2+2x+3x-3=0\)
\(\Leftrightarrow\left(x-\frac{1}{2}\right)\left(x+3\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x=\frac{1}{2}\\x=-3\end{cases}}\)
a)(3/2-0,5)/x=7/2+1/4
(3/2-1/2)/x=14/4+1/4
1/x=15/4
x=1:15/4
x=4/15
b)(x*0,25+2010)*2011=(53+2010)*(2012-1)
(x*0,25+2010)*2011=2063*2011
=>0,25x+2010=2063
0,25x=2063-2010
0,25x=53
x=53/0,25
x=212
\(a,\frac{-2}{3}\div\left(\frac{1}{2}-3x\right)=\frac{5}{3}\)
\(\frac{1}{2}-3x=\frac{-2}{3}\div\frac{5}{3}\)
\(\frac{1}{2}-3x=\frac{-2}{5}\)
\(3x=\frac{1}{2}-\frac{-2}{5}\)
\(3x=\frac{9}{10}\)
\(x=\frac{9}{10}\div3=\frac{3}{10}\)
\(b,\frac{1}{7}\left|x\right|-\frac{4}{5}=\frac{1}{5}\)
\(\frac{1}{7}\left|x\right|=\frac{1}{5}+\frac{4}{5}=1\)
\(\left|x\right|=1\div\frac{1}{7}=7\)
\(\Leftrightarrow x=\pm7\)
-2/3:(1/2-3x)=5/3
(1/2-3x)=5/3.-3/2
(1/2-3x)=-5/2
3x=-5/2+1/2
3x=-3/2
x=-3/2:3/1
x=-3/2.1/3
x=-1/2
\(\left(\frac{7}{2}+2x\right).\frac{8}{3}=\frac{16}{3}\)
\(\frac{7}{2}+2x=\frac{16}{3}:\frac{8}{3}\)
\(\frac{7}{2}+2x=2\)
\(2x=2-\frac{7}{2}\)
\(2x=\frac{-3}{2}\)
\(x=\frac{-3}{2}:2\)
\(x=\frac{-3}{4}\)
\(\frac{1}{3}.x+0,5x=0,75\)
\(\frac{1}{3}x+\frac{1}{2}x=\frac{3}{4}\)
\(x.\left(\frac{1}{3}+\frac{1}{2}\right)=\frac{3}{4}\)
\(x.\frac{5}{6}=\frac{3}{4}\)
\(x=\frac{3}{4}:\frac{5}{6}\)
\(x=\frac{9}{10}\)
Giải:
\(\left(x.0,5-\dfrac{3}{7}\right):\dfrac{1}{2}=1\dfrac{1}{7}\)
\(\Leftrightarrow\left(x.0,5-\dfrac{3}{7}\right).2=\dfrac{8}{7}\)
\(\Leftrightarrow x-\dfrac{6}{7}=\dfrac{8}{7}\)
\(\Leftrightarrow x=\dfrac{8}{7}+\dfrac{6}{7}\)
\(\Leftrightarrow x=\dfrac{14}{7}=2\)
Vậy ...